First, find the value of the expression within the parentheses, which is 8x. Since x=1/4, 8x=8/4 or 2. Next, multiply this value by -3. -3*2=-6
Answer:
<h3>The given polynomial of degree 4 has atleast one imaginary root</h3>
Step-by-step explanation:
Given that " Polynomial of degree 4 has 1 positive real root that is bouncer and 1 negative real root that is a bouncer:
<h3>To find how many imaginary roots does the polynomial have :</h3>
- Since the degree of given polynomial is 4
- Therefore it must have four roots.
- Already given that the given polynomial has 1 positive real root and 1 negative real root .
- Every polynomial with degree greater than 1 has atleast one imaginary root.
<h3>Hence the given polynomial of degree 4 has atleast one imaginary root</h3><h3> </h3>
12) 2.3
13) 4/13
14) 8 7/11
7) .3434...
8) 3.166...
15) (2700-600)/2700 = 2100/2700 = 21/27 = 7/9
1) .4666666667
2) .4444...
3) -0.6666666667
4) -0.8571428571
5) 3.3409090909...
6) -2.227272727273
**bar notation is when you put a bar over the repeating part of a decimal because you can't right it all since it goes on forever
This is an exponential function.
If x = 0, 2^x = 2^0 = 1. The beginning value of 2^x is 1 and the beginning value of 51*2^x is 51.
Make a table and graph the points:
x y=51*2^x point (x,y)
-- --------------- ---------------
0 51 (0,51)
2 51*2^2 = 51(4) = 204 (2,204) and so on.
The graph shows up in both Quadrants I and II. Its y-intercept is (0,51). Its slope is always positive.
Answer:
one bag of popcorn costs - 5
Step-by-step explanation:
