Answer:
1.544*10⁹ Linebackers would be required in order to obtain the same density as an alpha particle
Step-by-step explanation:
Assuming that the pea is spherical ( with radius R= 0.5 cm= 0.005 m), then its volume is
V= 4/3π*R³ = 4/3π*R³ = 4/3*π*(0.005 m)³ = 5.236*10⁻⁷ m³
the mass in that volume would be m= N*L (L= mass of linebackers=250Lbs= 113.398 Kg)
The density of an alpha particle is ρa= 3.345*10¹⁷ kg/m³ and the density in the pea ρ will be
ρ= m/V
since both should be equal ρ=ρa , then
ρa= m/V =N*L/V → N =ρa*V/L
replacing values
N =ρa*V/L = 3.345*10¹⁷ kg/m³ * 5.236*10⁻⁷ m³ /113.398 Kg = 1.544*10⁹ Linebackers
N=1.544*10⁹ Linebackers
Answer:
m<T = , m<M = and m<Z =
Step-by-step explanation:
From the given ∆TMZ, let the measure angle T be represented by T.
So that,
m<M = 2T + 6°
m<Z = 5T - 50°
Sum of angles in a triangle =
T + (2T + 6°) + (5T - 50°) =
8T - =
8T = +
=
T =
=
Therefore,
i. m<T =
ii. m<M = 2T + 6°
= 2 x + 6°
=
m<M =
iii. m<Z = 5T - 50°
= 5 x - 50°
= - 50°
=
m<Z =
Answer: The angle is 105 degrees. This angle along with the 75 degree angle make a straight line , 180-75 = 105 degrees
Based on the given puzzle above by crafty grandma Edith and was answered by her six-year-old granddaughter, the correct answer would be 3. 9183 is equals to 3. Hope this is also the answer that you are looking for. Have a great day!
Answer: 31/35
Step-by-step explanation:
