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evablogger [386]
3 years ago
5

Crafty grandma Edith set her family down during Thanksgiving and told them they couldn't have any pet can pass until they worked

out this puzzle are six-year-old granddaughter was the first to solve it can you work out what 9183 equals
8809=6 3590=2
7111=0 6855=3
9881=5 1012=1
6660=4 5731=0
5531=0 9191=2
2516=1 9193=?
Mathematics
1 answer:
Jet001 [13]3 years ago
5 0
Based on the given puzzle above by crafty grandma Edith and was answered by her six-year-old granddaughter, the correct answer would be 3. 9183 is equals to 3. Hope this is also the answer that you are looking for. Have a great day!
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91/50 as a decimal and percent
Anarel [89]

Answer:

Decimal: 1.82. Percent: 182%

Step-by-step explanation:


3 0
3 years ago
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Can someone help me with this?
JulijaS [17]

Answer:

19.53

Step-by-step explanation:

First let's find the new price of the backpack:

40% of 29.99 is

29.99 * 0.40 = 11.99

So the new price of the backpack is

29.99 - 11.99 = 18.00

Now let's find the price with tax

8.5% of 18.00 is

18.00 * 0.085 = 1.53

So the cost of the backpack is

18.00 + 1.53 = $19.53

8 0
3 years ago
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What is 1000 k = to but it has to be a gram .any get it cause I don't help me
denpristay [2]
You need to convert 1000kg to grams? There are 1000g\frac{1000g}{kg}
Now what you need to do is multiply the number of kg you have by your conversion fractions, making sure that grams is on top so you end up with grams in your answer:\frac{1000kg}{g} * \frac{1000g}{kg}

Kg cancel, and you are left with 1,000,000g
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Hope this helps!
5 0
3 years ago
Please help, I’ve been stuck on this question for about a hour now.
Hoochie [10]
6x + 5x + (x + 16) + (3x - 1) = 360
11x + x + 16 + 3x - 1
15x + 15 = 360
15x = 345
x = 23


6(23) = 138
((23) + 16) = 39
(3(23) - 1) =68
5(23) = 115

138 + 39 + 68 + 115 = 360
7 0
3 years ago
Calculate s f(x, y, z) ds for the given surface and function. g(r, θ) = (r cos θ, r sin θ, θ), 0 ≤ r ≤ 4, 0 ≤ θ ≤ 2π; f(x, y, z)
Triss [41]

g(r,\theta)=(r\cos\theta,r\sin\theta,\theta)\implies\begin{cases}g_r=(\cos\theta,\sin\theta,0)\\g_\theta=(-r\sin\theta,r\cos\theta,1)\end{cases}

The surface element is

\mathrm dS=\|g_r\times g_\theta\|\,\mathrm dr\,\mathrm d\theta=\sqrt{1+r^2}\,\mathrm dr\,\mathrm d\theta

and the integral is

\displaystyle\iint_Sx^2+y^2\,\mathrm dS=\int_0^{2\pi}\int_0^4((r\cos\theta)^2+(r\sin\theta)^2)\sqrt{1+r^2}\,\mathrm dr\,\mathrm d\theta

=\displaystyle2\pi\int_0^4r^2\sqrt{1+r^2}\,\mathrm dr=\frac\pi4(132\sqrt{17}-\sinh^{-1}4)

###

To compute the last integral, you can integrate by parts:

u=r\implies\mathrm du=\mathrm dr

\mathrm dv=r\sqrt{1+r^2}\,\mathrm dr\implies v=\dfrac13(1+r^2)^{3/2}

\displaystyle\int_0^4r^2\sqrt{1+r^2}\,\mathrm dr=\frac r3(1+r^2)^{3/2}\bigg|_0^4-\frac13\int_0^4(1+r^2)^{3/2}\,\mathrm dr

For this integral, consider a substitution of

r=\sinh s\implies\mathrm dr=\cosh s\,\mathrm ds

\displaystyle\int_0^4(1+r^2)^{3/2}\,\mathrm dr=\int_0^{\sinh^{-1}4}(1+\sinh^2s)^{3/2}\cosh s\,\mathrm ds

\displaystyle=\int_0^{\sinh^{-1}4}\cosh^4s\,\mathrm ds

=\displaystyle\frac18\int_0^{\sinh^{-1}4}(3+4\cosh2s+\cosh4s)\,\mathrm ds

and the result above follows.

4 0
3 years ago
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