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3 years ago

Can someone please help me with question no. 3.2.2

Mathematics

1 answer:

Paul [167]3 years ago

7 0

so the train departed Durban at 18:30 in 24hours format, or namely 6:30pm, and arrived at Kimberly at 14:50 on the next day, namely 2:50pm Thursday.

let's see, from 6:30 to 7pm is 30 minutes

from 7pm to 12am or 00:00 is 5 hours

and from 12am to 2:50 or namely 00:00 to 14:50 is well, 14 hours and 50 minutes

if we add the hours first, that'd be 5 + 14 = 19, and then we add the minutes that'd be 30 + 50 = 80 minutes, so that'd be a total of 19 hours and 80 minutes, wait a second!!!, 80 minutes is really 60 + 20, or 1 hour and 20 minutes, so that'd make it 19 hours plus 1 hour and 20 minutes, 20 hours and 20 minutes.

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Takala put 9 marbles in the box, jackie put in 7, and laird put in 11. Then they divided the marbles evenly among themselves. Ho

Georgia [21]

Answer:

The correct answer is 9.

Step-by-step explanation:

Let's start by analyzing the information we have.

We know that Takala put 9 marbles in the box, jackie put in 7, and laird put in 11.

Before continuing, the most convenient is to add these three things:

9 + 7 + 11 = 27.

We now know that those 27 were divided equally to each other, that is 27: 3.

So we just have to divide:

27: 3 = 9

In this way we can verify that each person obtained 9.

4 0

3 years ago

Which function represents the graph of h(x)=2∣∣x+3∣∣−1h(x)=2|x+3|−1 after it is translated 2 units right?

frosja888 [35]

C because i learned it from xxxx xxx

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4 years ago

Calculate two iterations of Newton's Method to approximate a zero of the function using the given initial guess. (Round your ans

VikaD [51]

Answer:

The two iterations of f(x) = 1.5598

Step-by-step explanation:

If we apply Newton's iterations method, we get a new guess of a zero of a function, f(x), xₙ₊₁, using a previous guess of, xₙ.

xₙ₊₁ = xₙ - f(xₙ) / f'(xₙ)

Given;

f(xₙ) = cos x, then f'(xₙ) = - sin x

cos x / - sin x = -cot x

substitute in "-cot x" into the equation

xₙ₊₁ = xₙ - (- cot x)

xₙ₊₁ = xₙ + cot x

x₁ = 0.7

first iteration

x₂ = 0.7 + cot (0.7)

x₂ = 0.7 + 1.18724

x₂ = 1.88724

second iteration

x₃ = 1.88724 + cot (1.88724)

x₃ = 1.88724 - 0.32744

x₃ = 1.5598

To four decimal places = 1.5598

4 0

3 years ago

A child wanders slowly down a circular staircase from the top of a tower. With x,y,zx,y,z in feet and the origin at the base of

babymother [125]

Answer:

a) The tower is 90 feet tall

b) She reaches the bottom at t = 18 minutes.

c) Her speed at time t is 5 \sqrt[]{5} ft/minute

d) Her acceleration at time t is 10 ft/minute^2

Step-by-step explanation:

Consider the path described by the child as going down the tower to have the following parametrization $\gamma(t) = (10\cos t, 10 \sin t, 90-5t)$

a) Assuming that the child is at the top of the tower when she starts going down, we have that at the initial time (t=0) we will have the value of the height of the tower. That is z = 90-5*0 = 90 ft.

b) The child reaches the bottom as soon as z =0. We want to find the value of t that does that. Then we have 0 = 90-5t, which gives us t = 18 minutes.

c) Given the parametrization we are given, the velocity of the child at time t is given by $\frac{d\gamma}{dt}= (\frac{d}{dt}(10\cos t), \frac{d}{dt} (10 \sin t ), \frac{d}{dt}(90-5t)) = (-10 \sin t, 10 \cos t, -5)$ . The speed is defined as the norm of the velocity vector,

so, the speed at time t is given by $v = \sqrt[]{(-10 \sin t)^2+(10 \cos t)^2+(-5)^2} = \sqrt[]{100(\sin^2 t + \cos^2 t)+25} = \sqrt[]{125}= 5 \sqrt[]{5}$