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zhenek [66]
3 years ago
15

STRUGGLING please please help. Include explanation if possible

Mathematics
1 answer:
Mariana [72]3 years ago
5 0

Given

two angles (150° and 12°) and the shortest side (12 cm) of a triangle

Find

the second-shortest side

Solution

Strategy: Make use of the Law of Sines to find missing side lengths when angles are known. To find the third angle, make use of the sum of angles of a triangle.

The sum of angles of a triangle is 180°, so we have

... 150° + 12° + C = 180°

... C = 180° - 162° = 18°

The law of sines tells us

... c/sin(C) = b/sin(B)

... c = sin(C)·b/sin(B) = sin(18°)·(10 cm)/sin(12°)

... c ≈ 14.9 cm

_____

We are calling the sides a, b, c. We are calling the angles opposite those sides A, B, and C.

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Miki, a resident of Kyoto, earns an annual salary of ¥6,760,950. If the Japanese government levies a 29.12% income tax on Miki’s
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Find 29.12% of 6,760,950. You can do this by converting 29.12% to a decimal by moving the decimal 2 places to the left and getting rid of the percent sign. Do this and you figure out 29.12% is .2912 as a decimal. Now you multiply this decimal with 6,760,950 to find what the government takes for taxes from his annual salary. You get 1,968,788.64. This is not your final answer because you want to find the amount of money he keeps after taxes. So you'd subtract 1,968,788.64 from 6,760,950. This gives you 4,792,161.36. This is his take-home pay, but you have to round to the nearest yen, so your final answer is 4,792,161.
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el perimetro de un terreno rectangular es de 170m y su area es de 170^2hallar la medida de sus lados con ecuacion cuadratica
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Answer:

Acá tenemos un sistema de ecuaciones.

El perímetro de un rectángulo es:

2*A + 2*L = 170m

donde A es el ancho y L es el largo.

Y el área del rectángulo es:

A*L = 170m^2.

Entonces, el primer paso es aislar una de las variables en una de las ecuaciones, yo voy a aislar A en la segunda:

A = 170m^2/L.

Ahora reemplazo eso en la primera ecuación y la resuelvo para L.

2*( 170m^2/L.) + 2*L = 170m.

340m^2 + 2*L^2 = 170m*L

ahora tenemos una ecuación cuadrática:

2*L^2 - 170m*L + 340m^2 = 0.

Las soluciones se pueden obtener usando la formula de Bhaskara:

L = \frac{+170 +- \sqrt{170^2 -4*340*2}  }{2*2} = \frac{170 +-161.8}{4}

Entonces las soluciones son:

L = (170 + 161.8)/4 = 82.95m

L = (170 - 161.8)/4 = 4.1m

Entonces, si tomamos L = 82.95m, tenemos A = 4.1 m

y el área es:

A*L = 4.1m*82.95m = 170m^2

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