Answer:
1.030-0.545=0.485 grams of oxygen in compound.
Convert grams of Al and grams of O into moles:
0.545g Al x 1 mol Al/26.98g Al = 0.0202 mol Al
0.485g O x 1 mol O/16.00g O = 0.0303 mol O
Next we divide the moles of both of them by the lowest number to get simplest ratio
0.0202/0.0202 = 1 Al
0.0303/0.0202 = 1.5 O
Next we multiply all numbers until we get a whole number for each one. In this case 2 works:
Al 1 x 2 : O 1.5 x 2
and we are left with Al2O3
Explanation:
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