Question

Jake and each of his brothers choose a fraction between 0 and 1.Jake chooses 3/4,Aaron chooses 9/10, and Simon choses 4/12. Which is a group of fractions that includes an equivalent fraction for each of the fractions 3/4,9/10, and 4/12? a. 3/8, 9/100, 1/4 b. 3/8, 90/100, 1/3 c. 9/12, 90/100,1/3 d. 9/12, 90/100, 1/4

Answer 1

Answer:

c. 9/12, 90/100,1/3

Step-by-step explanation:

3/4,   *3=9/12

9/10  *10 =90/100

4/12   divided into 4 = 1/3

Answer 2

Answer:

Option C.

Step-by-step explanation:

It is given that Jake chooses 3/4, Aaron chooses 9/10, and Simon chooses 4/12.

We need to find the  group of fractions that includes an equivalent fraction for each of the fractions 3/4,9/10, and 4/12.

Equivalent fraction:

$\dfrac{a}{b}\equiv \dfrac{ka}{kb}$

where, k is a constant.

The given fracions can be rewritten as

$\dfrac{3}{4}=\dfrac{3}{4}\times \dfrac{3}{3}=\dfrac{9}{12}$

$\dfrac{9}{10}=\dfrac{9}{10}\times \dfrac{10}{10}=\dfrac{90}{100}$

$\dfrac{4}{12}=\dfrac{1\times 4}{3\times 4}=\dfrac{1}{3}$

The equivalent fraction for each of the fractions 3/4,9/10, and 4/12 are 9/12, 90/100,1/3 respectively.

Therefore, the correct option is C.