Question

Which expression is equivalent to 9x^5+3x(4x^4-3x^2)^2

Answer 1

48x^9−72x^7+36x^5 I got this by,
Let's simplify step-by-step.9x5+3x(4x4−3x2)2Distribute:=9x5+48x9+−72x7+27x5Combine Like Terms:=9x5+48x9+−72x7+27x5=(48x9)+(−72x7)+(9x5+27x5)=48x9+−72x7+36x5

Answer 2

Answer:

$48x^9-72x^7+36x^5$

Step-by-step explanation:

The initial expression is:

$9x^5+3x(4x^4-3x^2)^2$

First expand the squared part (inside the parenthesis):

$9x^5+3x(4x^4-3x^2)(4x^4-3x^2)\\9x^5+3x(16x^8-24x^6+9x^4)$

Then, multiply the terms inside the parenthesis by 3x applying the distributive property:

$9x^5+3x(16x^8-24x^6+9x^4)\\9x^5+48x^9-72x^7+27x^5$

Finally add terms with the same exponent

$48x^9-72x^7+36x^5$