Question

The equation for the line of best fit is f(x) ≠1. 8x ⒠5. 4 for the set of values in the table. A 2-column table with 7 rows. The first column is labeled x with entries 4, 5, 6, 6, 8, 9, 10. The second column is labeled f(x) with entries 5, 2, 5, 6, 8, 7, 18. Using the equation for the line of best fit, what is a good approximation for x when f(x) = 30? 14 20 45 54.

Answer 1

The equation for the line of best fit, the good approximation for x when f(x) = 30 is 20.

Given that

The equation for the line of best fit is f(x) = 1.8x − 5.4 for the set of values in the table.

A 2-column table with 7 rows.

The first column is labeled x with entries 4, 5, 6, 6, 8, 9, 10.

The second column is labeled f(x) with entries 5, 2, 5, 6, 8, 7, 18.

We have to determine

Using the equation for the line of best fit, what is a good approximation for x when f(x) = 30?

According to the question

The quadratic regression equation can be expressed as;

$\rm f(x) = 1.8x - 5.4$

Then,

The approximation for x when f(x) = 30 is,

$\rm f(x) = 1.8x - 5.4\\\\\rm 30= 1.8x - 5.4 \\\\ 1.8x= 30+5.4\\\\1.8x=35.4\\\\x = \dfrac{35.4}{1.4}\\\\x=19.67\\\\x=20 \ approx$

Hence, the equation for the line of best fit, the good approximation for x when f(x) = 30 is 20.

To know more about the Quadratic equation click the link given below.

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