How does using a model help me multiply decimals by whole numbers?

What is 36 and 8 greatest common factor

defon

Answer:

The answer is 4

Step-by-step explanation:

4x9=36

2x4=8

Hope this helps

8 0

3 years ago

Read 2 more answers

I was wondering what is 9/2 divided by 1/2

liubo4ka [24]

Answer:

$\frac{18}{2}$ or 9

Step-by-step explanation:

1. Set up the problem: $\frac{9}{2}$ ÷ $\frac{1}{2}$

2. Replace the division sign with a multiplication sign: $\frac{9}{2}$ × $\frac{1}{2}$

3. Find the reciprocal by swapping the numerator and denominator on the second fraction: $\frac{9}{2}$ × $\frac{2}{1}$

4. Multiply fractions: $\frac{9}{2}$ × $\frac{2}{1}$ = $\frac{18}{2}$ or 9

6 0

3 years ago

Two times the sum of a number and 9 is half the number

Pavel [41]

Answer:

Equation:

2(a+9) = a/2

Solve:

The umber is:

-12

Step-by-step explanation:

Equation:

2(a+9) = a/2

Solve:

2*a + 2*9 = a/2

2a + 18 = a/2

2a - a/2 = -18

4a/2 - a/2 = -18

3a/2 = -18

a = -18*2/3

a = -12

Check:

2(-12+9) = -12/2

2(-3) = -12/2 = -6

4 0

3 years ago

How many area codes (abc) would be possible if all three digits could be any vaiue 1-9

kifflom [539]

Answer:

The total number of area codes that would be possible if all three digits could be any value from 1 to 9 is 729.

Step-by-step explanation:

1. Let's start our reasoning to get this answer:

From 000 to 999, we have 1,000 possible area codes.

But for this question, we should find out the answer without considering the digit 0, therefore we must exclude:

A. From 000 to 099, that are 100 possible area codes.

B. We also have to exclude, from 100 to 110, 120, 130, 140, 150, 160, 170, 180 and 190. Those are 19 area codes more.

C. We also have to exclude these same options of code areas, for 200 - 210 and 2x0, and 19 more for each subset that starts with 3, 4, 5, 6, 7, 8 and 9. In total, 19 multiplied by 8, 152 numbers more.

Therefore, the total number of area codes that would be possible if all three digits could be any value from 1 to 9 is:

1,000 - 100 - 19 - 152 = 729

The simplest way to find it, is:

For 000 to 999 = 1,000 or 10³

Excluding the digit zero = 729 or 9³

3 0

3 years ago

The hypotenuse of a right triangle is 15 inches. One of the legs is 3 inches more than the other. Find the length of the two leg

Crank

Let x = one of the legs.

Then, the other leg = x + 3.

Ed will use the Pythagorean Theorem to find the hypotenuse.

So, let a = x one leg. Let b= x + 3 the other leg. And, let c = 15 the hypotenuse.

The Pythagorean Theorem is:

c^2 = a^2 + b^2, where a and b are the legs and c is the hypotenuse.

We have:

15^2 = x^2 + (x + 3)^2

225 = x^2 + x^2 + 6x + 9

Rearranging:

2x^2 + 6x - 216 = 0

Divide by 2:

x^2 + 3x - 108 = 0

Solve by factoring:

(x - 9)(x + 12) = 0

So, x = 9 and x = -12. (x = -12 is not a valid answer.)

x = 9

x + 3 = 12

Conclusion: The legs of the right triangle are 9 inches and 12 inches.

Eddie-G…

3 0

3 years ago