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Kipish [7]
3 years ago
7

How many area codes (abc) would be possible if all three digits could be any vaiue 1-9

Mathematics
1 answer:
kifflom [539]3 years ago
3 0

Answer:

<u>The total number of area codes that would be possible if all three digits could be any value from 1 to 9 is 729.</u>

Step-by-step explanation:

1. Let's start our reasoning to get this answer:

From 000 to 999, we have 1,000 possible area codes.

But for this question, we should find out the answer without considering the digit 0, therefore we must exclude:

A. From 000 to 099, that are 100 possible area codes.

B. We also have to exclude, from 100 to 110, 120, 130, 140, 150, 160, 170, 180 and 190. Those are 19 area codes more.

C. We also have to exclude these same options of code areas, for 200 - 210 and 2x0, and 19 more for each subset that starts with 3, 4, 5, 6, 7, 8 and 9. In total, 19 multiplied by 8, 152 numbers more.

<u>Therefore, the total number of area codes that would be possible if all three digits could be any value from 1 to 9 is:</u>

<u>1,000 - 100 - 19 - 152 = 729</u>

<u>The simplest way to find it, is:</u>

<u>For 000 to 999 = 1,000 or 10³</u>

<u>Excluding the digit zero = 729 or 9³</u>

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Which rational number is one tick mark to the left of -3/4
Zolol [24]

I'm assuming each tickmark is 1/4 = 0.25

If that assumption is correct, then going one tickmark to the left of -3/4 lands you on -4/4 which simplifies to -1.

So -1 is one tickmark to the left of -3/4

Again, this all hinges on the assumption that each tickmark is 1/4 a unit away from its neighbor.

5 0
3 years ago
3.1 Find the equation of the line passing through (4, 5) and parallel to the line 3x – 2y = 4.
valentinak56 [21]

                   \rule{50}{1}\large\blue\textsf{\textbf{\underline{Question:-}}}\rule{50}{1}

            <em>Find the equation of the line passing through (4, 5) and parallel to </em>

<em>                 3x-2y=4.</em>

<em />

<em>  </em>\rule{50}{1}\large\blue\textsf{\textbf{\underline{Answer and how to solve:-}}}\rule{50}{1}

First of all, We need to convert this equation from standard form (ax+by=c) into slope-intercept form (y=mx+b).

\rightarrow First, add 2y on both sides:-

                            \Large\textsf{3x+2y=4}

\rightarrow Now, subtract 3x on both sides:-

                  \Large\textsf{2y=-3x+4}

\rightarrow Divide by 2 on both sides

    \Large\text{$y=-\displaystyle\frac{3}{2}x +2$}

\rule{300}{3}

Now, let's find the equation of the line that's parallel to the given line.

Remember, if lines are parallel to each other, then their slope's the same.

So the slope of the line that's parallel to the line whose equation we just found, is

\Large\text{$-\displaystyle\frac{3}{2}$}

Now let's write the equation in point-slope form:-

\hookrightarrow\sf{y-y_1=m(x-x_1)}

Replace numbers with letters, as follows:-

\sf{y-5=-\displaystyle\frac{3}{2} (x-4)}

The equation above is the equation in point-slope form.

Incase you need it converted to slope intercept form, refer to the steps below ~

Multiply -3/2 times x and -4:-

\hookrightarrow\sf{y-5=-\displaystyle\frac{3}{2} x-6}

Now, Add 5 on both sides:-

\hookrightarrow\sf{y=\displaystyle\frac{3}{2} x+1}

\Uparrow\sf{Our\:equation\:in\:slope\;intercept\;form}

<h3>Good luck with your studies.</h3>

#TogetherWeGoFar

\rule{300}{1}

4 0
2 years ago
The sum of three consecutive integers is 267. What is the largest integer?
vazorg [7]

Answer:

<h3>                90</h3>

Step-by-step explanation:

The middle number of three consecutive integers is thhe mean of the others, so it is one third of the sum of three consecutive integers

267:3 = <u>89 </u>  - the middle number

so:

89 - 1 = 88   -  the smallest number

89 + 1 =<u> 90</u> - the largest integer

3 0
3 years ago
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