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Mrrafil [7]
3 years ago
11

The variables X, Y, and Z represent polynomials where X = a, Y = 3a – 5, and Z = a2 + 2. What is X2Y – Z in simplest form?

Mathematics
2 answers:
raketka [301]3 years ago
5 0

Answer:B

Step-by-step explanation:

creativ13 [48]3 years ago
3 0

Answer:

3a^3-6a^2-2

Step-by-step explanation:

Given

  • x=a
  • y=3a-5
  • z=a^2+2

We need to find the expression for x^2y-z in simplest form. Hence we plug in the substitutions into the expression and simplify:

x^2y-z\\=(a)^{2}(3a-5)-(a^2+2)\\=3a^3-5a^2-a^2-2\\=3a^3-6a^2-2

2nd answer choice is right.

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what is the equation of the line in point slope form that goes through (-2,-1) and is perpendicular to y=5x+3?
stich3 [128]
Point slope form is y-y1=m(x-x1)

Since we have to write the equation of a perpendicular line we will have to use the slope that is opposite and reciprocal.

y - (-1) = - \frac{1}{5} (x - (-2))
y + 1 = - \frac{1}{5} (x + 2)

Hope this helps :)
8 0
3 years ago
Help! Pls! I’ll mark you as top
inysia [295]
10 1/2x +2

- because you would add all the side lengths, so 2x+2x+ 3 1/4x+ 13 1/4x 1. You can combine like terms it to 10 1/2x+ 2.
7 0
3 years ago
Use the graph to write an equation<br> y = acos[b(x – h)] + k to model the situation.
inna [77]

Answer:The amplitude:30

so a:-30

the period is:12

so b: pi/6

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
F divides HJ in the ratio 3:1. If H = (-11,7) and J = (5,3), what are the<br> coordinates of F?
Hatshy [7]

Answer:

The coordinates of HF are (1, 4)

Step-by-step explanation:

The parameters of the line are;

The coordinate of the end points are H = (-11, 7), and J = (5, 3)

The ratio by which the point F divides the line = 3:1

The segments in the line are HF, and FJ

Therefore;

The fraction of the length of HJ that is represented by HF = 3/(3 + 1) × HJ = 3/4 × HJ

HF = 3/4 × HJ

Which gives the coordinates of the point F as follows;

Coordinate of F = (-11 +(5 - (-11))×3/4, 7 + (3 - 7)×3/4) =  (1, 4)

The coordinates of F are (1, 4)

We check the length of HF, from the equation for the length to of a line to get;

l = \sqrt{\left (y_{2}-y_{1}  \right )^{2}+\left (x_{2}-x_{1}  \right )^{2}}

l_{HF} = \sqrt{\left (4-7  \right )^{2}+\left (1-(-11)  \right )^{2}} = \sqrt{\left (-3  \right )^{2}+\left (12  \right )^{2}} = 3\cdot \sqrt{17}

Similarly, we check the length of HJ, to get;

l_{HF} = \sqrt{\left (3-7  \right )^{2}+\left (5-(-11)  \right )^{2}} = \sqrt{\left (-4  \right )^{2}+\left (16  \right )^{2}} = 4\cdot \sqrt{17}

The length of HF = 3·√(17)

The length of HJ = 4·√(17)

Therefore, from HF = 3/4× HJ, we have;

HF = 3/4 × 4·√(17) = 3·√(17)

Therefore, the coordinates of HF are (1, 4)

7 0
3 years ago
May someone help me on this please
dsp73
11.4~L\times\frac{1~pt}{0.47~L}=24.26~pt
to the nearest hundredth
5 0
4 years ago
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