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4 years ago

-x + y for x = -10 and y = 1

Mathematics

2 answers:

Nezavi [6.7K]4 years ago

7 0

-x + y
-10 + 1
-9

The answer for this question is -9 .

hodyreva [135]4 years ago

5 0

-(-10) + 1
10+1
=11
so the answer will be 11

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For extra credit please help solve

hammer [34]

Answer:

∠ ABC = 37°

Step-by-step explanation:

Angles on the circle subtended by the same arc are congruent.

∠ ABC and ∠ ADC are angles on the circle subtended by arc AC , then

∠ ABC = 37°

3 0

3 years ago

The scores and their percent of the final grade for a statistics student are given. What is the student's weighted mean score?

Phantasy [73]

Answer:

The student's weighted mean score is 92.2.

Step-by-step explanation:

To find the student's weighted mean scored, we multiply each grade by it's weight.

Grades and weights:

Homework: Grade of 86, weight of 20% = 0.2

Quiz: Grade of 87, weight of 5% = 0.05

Quiz: Grade of 91, weight of 5% = 0.05

Project: Grade of 98, weight of 45% = 0.45

Final Exam: Grade of 88, weight of 25% = 0.25.

What is the student's weighted mean score?

0.2*86 + 0.05*87 + 0.05*91 + 0.45*98 + 0.25*88 = 92.2

The student's weighted mean score is 92.2.

7 0

3 years ago

Triangle DEF (not shown) is similar to ABC shown, with angle B congruent to angle E and angle C congruent to angle F. The length

Bezzdna [24]

Answer:

Area of ΔDEF is $45\ cm^2$ .

Step-by-step explanation:

Given;

ΔABC and ΔDEF is similar and ∠B ≅ ∠E.

Length of AB = $2\ cm$ and

Length of DE = $6\ cm$

Area of ΔABC = $5\ cm^2$

Solution,

Since, ΔABC and ΔDEF is similar and ∠B ≅ ∠E.

Therefore,

$\frac{Area\ of\ triangle\ 1}{Area\ of\ triangle\ 2} =\frac{AB^2}{DE^2}$

Where triangle 1 and triangle 2 is ΔABC and ΔDEF respectively.

If two triangles are similar, then the ratio of the area of both triangles is proportional to the square of the ratio of their corresponding sides.

$\frac{5}{Area\ of\ triangle\ 2} =\frac{2^2}{6^2}\\ \frac{5}{Area\ of\ triangle\ 2}=\frac{4}{36}\\ Area\ of\ triangle\ 2=\frac{5\times36}{4} =5\times9=45\ cm^2$