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2 years ago

12

An equilateral triangle has a perimeter of 90 inches. Find the area of the equilateral triangle in simplest radical form.

1 answer:

KIM [24]2 years ago

6 0

Answer:

450

Step-by-step explanation:

If the perimeter is 90 inches then each side must equal 30 inches. To find the area of a triangle you mulptiply the base by the height and divide by 2. The base is 30 and the height is 30. 30*30=900. 900/2=450.

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Write an equation of a line passing through point p(4, 0) that is parallel to the line -x+2y=12

dedylja [7]

Answer:

y = $\frac{1}{2}$ x - 2

Step-by-step explanation:

Given parameters:

Coordinates = p(4,0)

Equation of the line -x+2y=12

Solution:

A line parallel to the given line will have the same slope as it is;

-x+2y=12

2y = x + 12

y = $\frac{1}{2}$ x + $\frac{12}{2}$

Since this conforms to y = mx + c where;

x and y are the coordinates

m is the slope

c is the intercept

Our slope is $\frac{1}{2}$

The equation of the line is

y = mx + c

let us find c;

c = y - mx

c = 0 - ( $\frac{1}{2}$ x 4)

c = -2

Now the equation of the line parallel to the line given is;

y = $\frac{1}{2}$ x - 2

7 0

3 years ago

NEED HELP WORTH 100 POINTS SHOW YOUR WORK PLEASE

tia_tia [17]

Answer:

Q1:

$-5\sqrt{27c^2}$

$-5\sqrt{27}\sqrt{c^2}$

$-5\times\sqrt{9} \sqrt{3} \sqrt{c^2}$

$-5\times3\sqrt{3}\sqrt{c^2}$

$-5\times3\sqrt{3}c$

$-15\sqrt{3}c$

Q2:

$5\sqrt{72}-3\sqrt{32}$

$5\sqrt{36} \sqrt{2} -3\sqrt{16} \sqrt{2}$

$5\times6\sqrt{2}-3\times4\sqrt{2}$

$30\sqrt{2}-12\sqrt{2}$

$18\sqrt{2}$

Q3:

$\sqrt{108yz}+3\sqrt{98yz}+2\sqrt{75yz}$

$\sqrt{36} \sqrt{3} \sqrt{yz} +3\sqrt{49} \sqrt{2} \sqrt{yz} +2\sqrt{25} \sqrt{3} \sqrt{yz}$

$6\sqrt{3}\sqrt{yz}+21\sqrt{2}\sqrt{yz}+10\sqrt{3}\sqrt{yz}$

$16\sqrt{3}\sqrt{yz}+21\sqrt{2}\sqrt{yz}$

Q4:

$\sqrt{15n^2}\sqrt{10n^3}$

$\sqrt{15}n\sqrt{10n^3}$

$\sqrt{15}n\sqrt{10}\sqrt{n^2}\sqrt{n}$

$\sqrt{15}\sqrt{10}n^2\sqrt{n}$

$\sqrt{5}\sqrt{3}\sqrt{5}\sqrt{2}n^2\sqrt{n}$

$5\sqrt{3}\sqrt{2}n^2\sqrt{n}$

$5\sqrt{6}n^2\sqrt{n}$

Q5:

$\frac{\sqrt{3x^2y^3}}{4\sqrt{5xy^3}}$

$\frac{\sqrt{3}xy\sqrt{y}}{4\sqrt{5}y\sqrt{x}\sqrt{y}}$

Cancel off $\sqrt{x}$ :

$\frac{\sqrt{3}y\sqrt{x}\sqrt{y}}{4\sqrt{5}y\sqrt{y}}$

Cancel off $y:$

$\frac{\sqrt{3}\sqrt{x}\sqrt{y}}{4\sqrt{5}\sqrt{y}}$

Cancel off $\sqrt{y} :$

$\frac{\sqrt{3}\sqrt{x}}{4\sqrt{5}}$

Multiply $\sqrt{5}$ on the numerator and denominator:

$\frac{\sqrt{3}\sqrt{x}\sqrt{5}}{4\sqrt{5}\sqrt{5}}$

$\frac{\sqrt{15}\sqrt{x}}{20}$

5 0

3 years ago

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klemol [59]

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8 0

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7 0

3 years ago

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ololo11 [35]

The answer is minus 666 that’s the answer byee

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3 years ago