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IgorLugansk [536]
3 years ago
9

Hi can you help me please?)

Mathematics
1 answer:
Ad libitum [116K]3 years ago
8 0

<em>To solve for a variable, you just need to isolate the variable to one side.</em>

<h3>7.</h3>

For this, just divide both sides by r and <u>your answer will be \frac{d}{r}=t</u>

<h3>8.</h3>

For this, divide both sides by nR and <u>your answer will be \frac{PV}{nR}=T</u>

<h3>9.</h3>

Firstly, multiply both sides by T: AT=FV-OV

Next, subtract FV on both sides of the equation: AT-FV=-OV

Lastly, multiply both sides by -1, and <u>your answer will be -AT+FV=OV</u>

<h3>10.</h3>

Firstly, multiply both sides by 1000: 1000C=Wtc

Lastly, divide both sides by tc and <u>your answer will be \frac{1000C}{tc}=W</u>

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The median weight for a 5 foot tall male to enlist in the US Army is 114.5 lbs. This weight can vary by 17.5 lbs. Write and solv
myrzilka [38]

An absolute value inequality that represents the weight of a 5-foot male who would not meet the minimum or maximum weight requirement allowed to enlist in the Army is 97 lbs < x < 132 lbs.

<h3>What are inequalities?</h3>

Inequalities help us to compare two unequal expressions. Also, it helps us to compare the non-equal expressions so that an equation can be formed.

It is mostly denoted by the symbol <, >, ≤, and ≥.

The median weight for a 5 foot tall male to enlist in the US Army is 114.5 lbs. This weight can vary by 17.5 lbs. Therefore, the inequality can be written as,

(114.5 - 17.5) lbs < x < (114.5 + 17.5) lbs

97 lbs < x < 132 lbs

Hence, an absolute value inequality that represents the weight of a 5-foot male who would not meet the minimum or maximum weight requirement allowed to enlist in the Army is 97 lbs < x < 132 lbs.

Learn more about Inequality:

brainly.com/question/19491153

#SPJ1

4 0
2 years ago
A right circular cylinder is inscribed in a sphere with diameter 4cm as shown. If the cylinder is open at both ends, find the la
SOVA2 [1]

Answer:

8\pi\text{ square cm}

Step-by-step explanation:

Since, we know that,

The surface area of a cylinder having both ends in both sides,

S=2\pi rh

Where,

r = radius,

h = height,

Given,

Diameter of the sphere = 4 cm,

So, by using Pythagoras theorem,

4^2 = (2r)^2 + h^2   ( see in the below diagram ),

16 = 4r^2 + h^2

16 - 4r^2 = h^2

\implies h=\sqrt{16-4r^2}

Thus, the surface area of the cylinder,

S=2\pi r(\sqrt{16-4r^2})

Differentiating with respect to r,

\frac{dS}{dr}=2\pi(r\times \frac{1}{2\sqrt{16-4r^2}}\times -8r + \sqrt{16-4r^2})

=2\pi(\frac{-4r^2+16-4r^2}{\sqrt{16-4r^2}})

=2\pi(\frac{-8r^2+16}{\sqrt{16-4r^2}})

Again differentiating with respect to r,

\frac{d^2S}{dt^2}=2\pi(\frac{\sqrt{16-4r^2}\times -16r + (-8r^2+16)\times \frac{1}{2\sqrt{16-4r^2}}\times -8r}{16-4r^2})

For maximum or minimum,

\frac{dS}{dt}=0

2\pi(\frac{-8r^2+16}{\sqrt{16-4r^2}})=0

-8r^2 + 16 = 0

8r^2 = 16

r^2 = 2

\implies r = \sqrt{2}

Since, for r = √2,

\frac{d^2S}{dt^2}=negative

Hence, the surface area is maximum if r = √2,

And, maximum surface area,

S = 2\pi (\sqrt{2})(\sqrt{16-8})

=2\pi (\sqrt{2})(\sqrt{8})

=2\pi \sqrt{16}

=8\pi\text{ square cm}

4 0
2 years ago
a knitted hat pattern comes in 4 styles with 4 stich options and 3 sizes and there are 7 yerans appropriate for the hart, disreg
Gwar [14]
112 let me explain

4 styles times 4 stitch options times 7 equals 112
7 0
3 years ago
Is 89 prime or composite
Ratling [72]
It is a prime number. 89=1×89 hope it helps
8 0
3 years ago
8(2x + 3x + 2) = -4x + 148 step by step?
SIZIF [17.4K]

Answer:

3

Step-by-step explanation:

distribute then combine like terms then subtract 16 from itself and 148 then 4 plus itself and 40 then 44 divide by 132

3 0
3 years ago
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