Question

A scuba diver 200 m underwater experiences a temperature of 15 oC and a pressure of

Answer 1

Answer:

The answer to your question is 4.2 l

Explanation:

Data

Temperature 1 = T1 = 15°C = 288ºK

Pressure 1 = P1 = 2 atm

Volume 1 = V1 = 2 l

Temperature 2 = T2 = 30°C = 303ºK

Pressure 2 = P2 = 1 atm

Volume 2 = V2 = ?

Formula

Combined gas law

                              $\frac{P1V1}{T1} = \frac{P2V2}{T2}$

Solve for V2

                              $V2 = \frac{P1V1T2}{P2T1}$

Substitution

                              $V2 = \frac{(2)(2)(303)}{(1)(288)}$

Simplification

                              $V2 = \frac{1212}{288}$

Result

                                     V2 = 4.2l