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2 years ago

During which change of state would the volume of a substance increase the most?

Chemistry

2 answers:

patriot [66]2 years ago

5 0

Answer:

vaporization

Explanation:

Alika [10]2 years ago

4 0

Answer:

The most state has the high volume is the gas state.

So here the answer is vaporization!!!!

Explanation:

The most state has the high volume is the gas state.

So here the answer is between vaporization and sublimation???

and when the sublimation is: the change of the material from the solid state to the gas state directly without pass to liquid state from the solid first then to the gas

and the vaporization is : The change of the material from the liquid state to the gas state by heating Ex: water vaporize at 100°

here, the answer is sublimation because the difference of volume which resulted from this process is more than the volume resulted from vaporization.

Plz mark brainlist!!

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2 years ago

How many mL of a stock solution of 2.00 M KNO3 are needed to prepare 100.0 mL of 0.15M KNO3? with work plz

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Using the law of dilution :

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2 years ago

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3 years ago

The heavier a gas molecule,

mr_godi [17]

Answer:

Explanation:

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3 years ago

For many purposes we can treat ammonia NH3 as an ideal gas at temperatures above its boiling point of −33.°C. Suppose the temper

Keith_Richards [23]

Answer:

The new pressure will be 0.225 kPa.

Explanation:

Applying combined gas law:

$\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}$

where,

$P_1\text{ and }V_1$ are initial pressure and volume at initial temperature $T_1$ .

$P_2\text{ and }V_2$ are final pressure and volume at initial temperature $T_2$ .

We are given:

$P_1=0.29 kPa\\V_1=V\\P_2=?\\V_2=V+50\% of V=1.5 V$

$T_1=-25^oC=248.15 K$

$T _2 = 16^oC=289.15 K$

Putting values in above equation, we get:

$\frac{0.29 kPa\times V}{248.15 K}=\frac{P_2\times 1.5V}{289.15 K}$

$P_1=0.225 kPa$

Hence, the new pressure will be 0.225 kPa.

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3 years ago