Answer:
number of moles of water (n) = 1.383 x10 ⁻⁵ mol
Explanation:
Data Given:
No. of molecules of water = 8.33×10¹⁸
No. of Mole of water = ?
Formula Used to calculate
no. of moles = numbers of particles (ions, molecules, atoms) /Avogadro's number
Avogadro's no. = 6.023 x10²³
So the formula could be written as
no. of moles (n) = no. of molecules of water /6.023 x10²³
Put the values in above formula
no. of moles (n) = 8.33×10¹⁸ /6.023 x10²³
no. of moles (n) = 8.33×10¹⁸ /6.023 x10²³
no. of moles (n) = 1.383 x10 ⁻⁵
so 1.383 x10 ⁻⁵ moles of water are represented by 8.33×10¹⁸ molecules of water.
Acid rain slowly dissolves rocks due to chemical reactions between the acid and the minerals in the rock. Differential Weathering: Softer, less resistant rocks wear away at a faster rate than more weather resistant rocks. More exposure to acid rain results in more rapid weathering.
Answer: kindly check explanation
Explanation:
Given the following :
Measured density of copper block:
8.6+/-0.2 g/cm3
True density = 8.96g/cm3
Standard deviation = 0.4g/cm
a. What is the high and low number of the confidence interval range?
High : 8.6 + 0.2 g/cm3 = 8.8g/cm³
Low : 8.6 - 0.2 g/cm3 = 8.4g/cm³
Does the true value fall within the confidence interval? NO
Actual density = 8.96g/cm³ doses not lie in between (8.4 - 8.8)g/cm³
B.) High and low of the standard deviation range?
High = 8.6 + 0.4 = 9.0g/cm³
Low = 8.6 - 0.4 = 8.2g/cm³
Value falls within range of the true density value of copper block.
8.96g/cm³ falls in-between (8.2-9.0)g/cm³
NH3 + H20 YIELDS NH4+ + OH-
So, the NH3 and the OH- are stoichiometrically equivalent.
So, we have 0.15M OH-
p OH = -log [OH-]
p OH = -log[0.15) = 0.824
pH = 14 - p OH
pH = 13.18
