3 years ago

UJ 1641"

Mathematics

1 answer:

Alekssandra [29.7K]3 years ago

7 0

Answer:

Step-by-step explanation:

You might be interested in

Urgenttttt please I need it fast

dolphi86 [110]

Answer:

Below in bold.

Step-by-step explanation:

c) 3 x (9^2)^3/4 x ((81^3)^5/6

= 3 x 81^3/4 x 81^15/6

= 3 x 81^(3/4 + 15/6)

= 3 x 81^13/4

= 3 x 3^13

= 3^14

= 4,782,969.

f) (5x^-1y^2)^-2 / (25 x^2 y - 1)^2

= 5^-2 x^2y^-4 / 625 x^4y^-2

= 5^-2 x^-2 y^-2 / 5^4

= 5^-6 x^-2y^-2

= 0.000064x^-2y^-2.

5 0

2 years ago

Suppose that 3 balls will be randomly put into 3 buckets, with each ball being equally likely to be put into each of the buckets

Yuliya22 [10]

Answer:

$\frac{1}{27}$

Step-by-step explanation:

Since there are a total of three buckets and only one can be chosen at a time, this would mean that the probability of a ball being placed in a bucket is 1/3. Since each ball has the same probability of being placed into any bucket regardless of the where the previous ball landed, it means that each ball has the same 1/3 probability of a bucket. In order to find the probability that all three land in the same bucket, we need to multiply this probability together for each one of the balls like so...

$\frac{1}{3} * \frac{1}{3} * \frac{1}{3} = \frac{1}{27}$