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jonny [76]
4 years ago
12

Which line is parallel to y= -52 + 6 and passes through (4, -2)?

Mathematics
1 answer:
Alexxandr [17]4 years ago
8 0

Answer:

\[y=-5x+18\]

Step-by-step explanation:

Given that the line is parallel to \[y = -5x + 6\]

Hence the slope of the line is given by -5

Hence the equation of the required line can be represented by \[y = -5x + c\]

This line passes through (4,-2). Substituting:

\[-2 = -5 * 4 + c\]

=> \[-2 = -20 + c\]

=> c = 20-2 = 18

So the required equation of the line is given by : \[y = -5x + 18\]

From the given options, option 3 is the correct one.

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The measure of Angle 2 is twelve less than five
hoa [83]

Answer: The measure of Angle 2 = 148°

Step-by-step explanation:

Given: The measure of Angle 2 is twelve less than five  times the measure of Angle 1.

Let the measure of Angle 1 = x

Then, measure of Angle 2 = 5x-12

Since both the angles form linear pair, so their sum = 180°  [linear pair of angles must add up to 180°.]

Then, x+ (5x-12) = 180

⇒ x+ 5x-12= 180

⇒ 6x-12= 180

⇒ 6x= 180+12

⇒ 6x= 192

⇒ x= 32  [divide both sides by 6 ]

So,  measure of Angle 2 = 5(32)-12 = 160-12 = 148°

Hence, the measure of Angle 2 = 148°

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3 years ago
PLEASE ANSWER ASAP!!! I WILL GIVE YOU 5 STARS AND BRAINLIEST!!
ehidna [41]

Answer:

j(x) = 2^(x - 5) - 2

Step-by-step explanation:

To the left of the y-axis we see that the blue graph is 2 units higher (vertically) than is the red graph.  This translation is shown in the formula h(x) = e^x + 2.  Beyond that, the graph of f(x) = 2^x has been translated 5 units to the right.

Thus, the "new" function is j(x) = 2^(x - 5) - 2

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The boys go to the store after their “Time-Out" to buy flowers for Lisa as
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In the function y=5x^2-2, what effect does the number 5 have on the graph, as compared to the graph of y=x^2?
allochka39001 [22]

General Idea:

The Rules for Transformations of Functions are given below:

If f(x) is the original function, a > 0 and c > 0; Then

f(x)+k \; \; shift \; f(x) \; UPWARD \; k \; units\\\\f(x)-k \; \; shift \; f(x) \; DOWNWARD \; k \; units\\\\f(x+h) \; \; shift \; f(x) \; LEFT \; h \; units\\\\f(x-h) \; \; shift \; f(x) \; RIGHT \; h \; units\\\\-f(x) \; \; REFLECT \; f(x) \; in \; the \; x-axis\\\\f(-x) \; REFLECT \; f(x) \; in \; the \; y-axis\\\\a \cdot f(x), \; a>1 \; STRETCH \; f(x) \; vertically \; by \; a \; factor \; of \; a\\\\a \cdot f(x), \; 0

f(ax), \; a>1 \; SHRINK \; f(x) \; horizontally \; by \; a \; factor \; of \;\frac{1}{a}  .\\\\f(ax), \; 0

Applying the concept:

In the function y=5x^2-2, the effect that the number 5 have on the graph, as compared to the graph of y=x^2 is given below:

C.it stretches the graph vertically by a factor of 5

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Step-by-step explanation:

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