The statement gives you the function that models the Area as a function of angle theta, and is telling the value of this angle.
Then, you only need to replace the value of the angle in the function, to obtain the requested area.
<span>A(Θ) = 16 sin Θ • (cos Θ + 1).
Θ = 60°
A(</span>60°<span>) = 16 sin(</span><span>60°) * [cos(</span><span>60°) + 1 ] = 16 * (√3) / 2 * [1/2 + 1] = 8(√3) * 3/2 = 12√3 ≈ 20.79
Answer: 20.8 in^2 </span>
Step-by-step explanation:
Solution,
According to question,
Length= 12 cm
Breadth= (12-2) cm= 10 cm
Now,
By using the formula of area of rectangle, we get
Area of rectangle= Length×breadth
Area of rectangle=12 cm×10 cm
Area of rectangle=120 cm²
Hence, the area of the rectangle is 120 cm².
Answer:
Determine the type of elasticity of demand
Answer:
30.3
Step-by-step explanation:
First we find the area of the trapezoid. The formula for that is (b1+b2)/2(h)
2+10=12
12/2=6
6x4=24
To find the area of a semicircle we do πr²/2
2^2=4
4x3.14=12.56
12.56/2=6.28
24+6.28=30.28
That is extremely close to 30.3 so the paper must be a bit off.
Answer:
A = 23°
b = 9.5
c = 14.7
Step-by-step explanation:
B = 32°
C = 125°
a = 7
✔️Find A:
A = 180° - (B + C) (sum of triangle)
A = 180° - (32° + 125°)
A = 23°
✔️Find b using Law of Sines:
Plug in the values
Cross multiply
Divide both sides by sin(23)
b = 9.5 (nearest tenth)
✔️Find c using Law of Sines:
Plug in the values
Cross multiply
Divide both sides by sin(23)
c = 14.7 (nearest tenth)
