Answer:
And if we solve for a we got
So the value of height that separates the bottom 20% of data from the top 80% is 23.432.
Step-by-step explanation:
Let X the random variable that represent the heights of a population, and for this case we know the distribution for X is given by:
Where
and
For this part we want to find a value a, such that we satisfy this condition:
(a)
(b)
As we can see on the figure attached the z value that satisfy the condition with 0.20 of the area on the left and 0.80 of the area on the right it's z=-0.842
If we use condition (b) from previous we have this:
But we know which value of z satisfy the previous equation so then we can do this:
And if we solve for a we got
So the value of height that separates the bottom 20% of data from the top 80% is 23.432.
Answer:
The solution region is x < –5 and x > 2
Step-by-step explanation:
We are given the inequalities, 2x–2 < –12 or 2x+3 > 7
Upon simplifying the inequalities, we get,
A. 
i.e.
i.e. 
B. 
i.e.
i.e. 
So, we get the solution is
or
and the plotted region can be seen below.
Parallel lines have the same slope.
So I plug in the -5 and -4
-4 = 1/2(-5) + b
-4 = -2.5 + b
b = -1.5
So I get y = 1/2x - 3/2
A^2+ b^2= c^2
24^2+b^2=25^2
576+b^2=625
Sub 576
b^2= 49 b=7
Answer:
5 pears
Step-by-step explanation:
Given that
The average of 20 pears were sold from Monday to Friday
But after the sales on Saturday and Sunday, the average pears sold per day were increased to 25
We need to determine the number of pears sold on Saturday and sunday
So, it is
= 25 pears - 20 pears
= 5 pears