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Varvara68 [4.7K]
3 years ago
12

Find the quotient9) 4,878​

Mathematics
1 answer:
guajiro [1.7K]3 years ago
8 0

Answer: 542

Step-by-step explanation:

The quotient is known as the final answer gotten after the value of 4878 has been divided using 9. The answer as such will be 542 (i.e 4878/9)

9 goes in 48 five times, 5 is written and remainder of 3 is kept above 7 to make it 37; then 9 goes in 37 four times, 4 is written and the reminder of 1 is written above 8 to make it 18; and finally 9 goes in 18 two times without remainder, then we write 2. Combining the answers gives our Final answer 542.

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Please help with geometry question
Hunter-Best [27]

Answer:

m∠J = 45° , m∠I = 45° and m∠M = 90°

And the ΔJIM is an isosceles right angled triangle.

Step-by-step explanation:

(a). In ΔJIM,

∠J = 2x + 15,

∠I = 5x - 30, and

∠M = 6x

Now, using angle sum property of a triangle that sum of all the angles in a triangle is 180°

⇒ ∠J + ∠I + ∠M = 180°

⇒ 2x + 15 + 5x - 30 + 6x = 180°

⇒ 13x -15 = 180°

⇒ 13x = 195

⇒ x = 15

Therefore, m∠J = 45° , ∠I = 45° and m ∠M = 90°

(b). Now, ΔJIM is a right angled triangle right angled at M.

Also, ∠J = ∠I = 45°

So, JM = IM ( because in a triangle sides opposite to equal angles are equal)

So, ΔJIM is an isosceles triangle because its two sides are equal.

Hence, ΔJIM is a right angled isosceles triangle right angled at M.

8 0
3 years ago
Convert 5.4 ⋅ 103 to standard form. 0.0054 0.00054 5,400 54,000
KATRIN_1 [288]
54*10 to the 3rd power equals 5'400
6 0
3 years ago
Three more than the quotient of a number and 5 is equal to 9
mars1129 [50]

Answer:

The number is 30.

Step-by-step explanation:

x/5+3=9

x/5=9-3

x/5=6

x=6*5

x=30

7 0
3 years ago
a lamp post cast a Shadow 15 feet long while a 6 foot man standing nearby cast a shadow 5 ft long. what proportion can be used t
kolezko [41]

Answer:

6/5=x/15

Step-by-step explanation:

6/5=x/15,where x is hight of the lamp post

x=18

3 0
3 years ago
Triangle ABC has vertices at A(2,3),B(-4,-3) and C(2,-3) find the coordinates of each point of concurrency.
dem82 [27]

Answer:

Circumcenter =(-1,0)

Orthocenter =(2,-3)

Step-by-step explanation:  

Given : Points A = (2,3), B = (-4,-3), C = (2,-3)  

Formula used :  

→Mid point of two points- (\frac{x_1+x_2}{2},\frac{y_1+y_2}{2})

→Slope of two points - \frac{y_2-y_1}{x_2-x_1})

→Perpendicular of a line = \frac{-1}{slope of line})

Circumcenter- The point where the perpendicular bisectors of a triangle meets.

Orthocenter-The intersecting point for all the altitudes of the triangle.

To find out the circumcenter we have to solve any two bisector equations.

We solve for line AB and AC

So, mid point of AB =(\frac{2-4}{2},\frac{3-3}{2})=(-1,0)

Slope of AB =\frac{-3-3}{-4-2}=1

Slope of the bisector is the negative reciprocal of the given slope.  

So, the slope of the perpendicular bisector = -1  

Equation of AB with slope -1 and the coordinates (-1,0) is,  

(y – 0) = -1(x – (-1))  

y+x=-1………………(1)  

Similarly, for AC  

Mid point of AC = (\frac{2+2}{2},\frac{3-3}{2})=(2,0)

Slope of AC = \frac{-3-3}{2-2}=\frac{-6}{0}  

Slope of the bisector is the negative reciprocal of the given slope.  

So, the slope of the perpendicular bisector = 0  

Equation of AC with slope 0 and the coordinates (2,0) is,  

(y – 0) = 0(x – 2)  

y=0 ………………(2)  

By solving equation (1) and (2),  

put y=0 in equation (1)

y+x=-1

0+x=-1

⇒x=-1  

So the circumcenter(P)= (-1,0)

To find the orthocenter we solve the intersections of altitudes.

We solve for line AB and BC

So, mid point of AB =(\frac{2-4}{2},\frac{3-3}{2})=(-1,0)

Slope of AB =\frac{-3-3}{-4-2}=1

Slope of the bisector is the negative reciprocal of the given slope.  

So, the slope of CF = -1  

Equation of AB with slope -1 and the coordinates (-1,0) gives equation CF  

(y – 0) = -1(x – (-1))  

y+x=-1………………(3)  

Similarly, mid point of BC =(\frac{-4+2}{2},\frac{-3-3}{2})=(-1,-3)

Slope of AB =\frac{-3+3}{-4-2}=0

Slope of the bisector is the negative reciprocal of the given slope.  

So, the slope of AD = 0

Equation of AB with slope 0 and the coordinates (-1,-3) gives equation AD

(y-(-3)) = 0(x – (-1))  

y+3=0

y=-3………………(4)  

Solve equation (3) and (4),

Put y=-3 in equation (3)

y+x=-1

-3+x=-1

x=2

Therefore, orthocenter(O)= (2,-3)


7 0
3 years ago
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