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iVinArrow [24]
2 years ago
11

2) -9(18+ 2x) show work

Mathematics
2 answers:
brilliants [131]2 years ago
6 0

Answer:

-162+(-18x)

Step-by-step explanation:

distribute

-9×18=-162

-9×2x=-18x

trasher [3.6K]2 years ago
5 0

Answer:

-162-18x

Step-by-step explanation:

-9(18+2x)

distribute the -9 into the (18+2x)

and ur left with -162-18x

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How do you write the following statement as an equation: a number N is 4 less than 8 ??
kiruha [24]
4 less than 8 is a number N

8 - 4 = n
or
n = 8 - 4
6 0
3 years ago
Slope intercept form for 1/-2
boyakko [2]

y= 1/-2x + b

The standard slope intercept form would be y =mx+b

"m" would be the increase/decrease or what makes the line go up or down,

and the "b" would be the height in which it starts at

Hope this helped.

7 0
3 years ago
The number of Blue Jays on a tree is 5 times of Red Robins. Combined there are a total of 48 birds on the tree. How many Blue Ja
LenKa [72]
8   48/6=8                          do you understand?     
8 0
3 years ago
HELP!!!!!!!!!!!!!
Misha Larkins [42]

Answer:

P'(7,0)Q'(2,1) R'(12,-6)

Step-by-step explanation:

P(3,5)------>P'(3+4,5-5)

P'(7,0)

Q(-2,6)----->Q'(-2+4,6-5)

Q'(2,1)

R(8,-1)------>R'(8+4,-1-5)

R'(12,-6)

8 0
3 years ago
Consider the function V=g(x), where g(x) =x(6-2x)(8-2x), with x being the length of a cutout in cm and V being the volume of an
Andrej [43]

Answer:

The maximum volume of the open box is 24.26 cm³

Step-by-step explanation:

The volume of the box is given as V=g(x), where g(x)=x(6-2x)(8-2x) and 0\le x\le3.

Expand the function to obtain:

g(x)=4x^3-28x^2+48x

Differentiate  wrt  x to obtain:

g'(x)=12x^2-56x+48

To find the point where the maximum value occurs, we solve

g'(x)=0

\implies 12x^2-56x+48=0

\implies x=1.13,x=3.54

Discard x=3.54 because it is not within the given domain.

Apply the second derivative test to confirm the maximum critical point.

g''(x)=24x-56, g''(1.13)=24(1.13)-56=-28.88\:

This means the maximum volume occurs at x=1.13.

Substitute x=1.13 into g(x)=x(6-2x)(8-2x) to get the maximum volume.

g(1.13)=1.13(6-2\times1.13)(8-2\times1.13)=24.26

The maximum volume of the open box is 24.26 cm³

See attachment for graph.

6 0
3 years ago
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