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KengaRu [80]
4 years ago
12

Which characteristics must an object possess in order to be considered alive?

Biology
1 answer:
worty [1.4K]4 years ago
7 0
<span>An object to be considered alive must have these characteristics.


1. Acquire and uses energy.
2. contains genetic programme.
3. composed of one more cells.
4. Respiration.
5. Must be able to grow.
6. Must be able to reproduce.
7. Must have a metabolism.
8. Must be able to respond to its environment. 9. Must be made of cells.</span>
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The light micrograph shows dividing cells near the tip of an onion root. Identify a cell in each of the following stages: propha
ad-work [718]

Mitotic division in onion root cells:

  1. Prophase: the emergence of chromatin threads that form chromosomes, the chromosomes are visible and overlap.
  2. Metaphase: chromosomes line up and line up in the middle of the equatorial plane. The centromere of the chromosome appears to have bonds with the kinetochores connected to the spindle threads.
  3. Anaphase: the centromere of the chromosome undergoes division then the chromosomes are pulled by the spindle threads towards the two opposite poles and leave the center of the equator that looks empty.
  4. Telophase: The cytoplasm divides into two identical-looking daughter cells. At the telophase stage, the process of cell division occurs in two parts and has identical properties.

Mitosis is a cell division through the stages of prophase, metaphase, anaphase, and telophase. The purpose of mitosis is for growth and regeneration which results in two daughter cells that are identical to the original parent cell. Mitosis occurs only once and lasts only during somatization.

Learn more about mitosis here brainly.com/question/1186551

#SPJ4

7 0
1 year ago
Two autosomal genes, J and K, are 60 map units apart. You perform the following testcross: J K / j k x j k / j k. At what freque
Dmitry [639]

Answer:

  • J K / j k = 20%
  • j k / j k = 20%
  • J k / j k = 30%
  • j K / j k = 30%                

Explanation:

To calculate the recombination frequency, we have to know that 1% of recombinations = 1 map unit = 1cm. And that the maximum recombination frequency is always 50%.

The map unit is the distance between the pair of genes for which every 100 meiotic products, one of them results in a recombinant one.

So, en the exposed example:

  • J and K are autosomal genes
  • J and K are separated by 60 M.U.
  • 60 M.U. means that there is 60% of recombination.

Cross)             J K / j k                    x                  j k / j k

Gametes) JK  Parental                                     jk, jk, jk, jk

                jk   Parental                                  

                Jk   Recombinant                          

                 jK   Recombinant

One map unit equals 1% of recombination frequency. This means that every 100 meiotic products, one of them is a recombinant one.

1 M.U. -------------- 1% recombination

60 M.U. ------------ 60% recombination

                              30% Jk  +  30% jK

100 M.U. - 60 M.U. = 40 M.U.

40M.U.--------------40 % Parental (Not recombinant)

                            20% JK   +   20% jk

Punnet Square)           JK       jk      Jk      jK

                          jk     JK/jk   jk/jk   Jk/jk   jK/jk

J K / j k = 20%

j k / j k = 20%

J k / j k = 30%

j K / j k = 30%                                

3 0
3 years ago
What type of relationship do the two species appear to have with each other
Artyom0805 [142]
Which 2 species? like I need to know in order to tell you
6 0
3 years ago
The data here indicates the number of species of amphibians that are affected by several factors in their environments.
Nana76 [90]

Answer:

b i hope it helps you !!!

Explanation:

7 0
3 years ago
Transpiration is the evaporation process used by plants for cooling and to regulate the amount of water within its body. Factors
Stella [2.4K]

Answer:

Transpiration is the process of water movement in the plant in which water is released from the leaves to the environment in the form of vapours.

The transpiration is important to the plant as:

1. Cooling Effect: Transpiration help lower down the temperature of the plant by evaporating water.

2. The ascent of Sap: leads to the uptake of water in the plant.

3.  Removal of Excess Water: removes extra water from the plant.

4. Maintain turgidity: helps maintain turgidity which leads to maintains shape and structure.

5. Photosynthesis: supplies water for the photosynthesis.

The process also has disadvantages to the plants as:

1.  Wilting: the excess loss of water causes wilting of leaves during noon.

2. Reduced Yield: the wilting reduces the formation of fruits, flowers and seeds.

3. Wastage of Energy: Loss of water leads to the waste of energy which is used in the conduction of water and absorption.

The climate change has changed the ability of the plants to undergo transpiration and plants has adapted to maintain equilibrium by producing hair, thorns, thick cuticle, sunken stomata, cladodes and phylloclades.

3 0
3 years ago
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