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svlad2 [7]
3 years ago
9

The students were told that the net applied force from the engine was the same for each vehicle tested. Based on this informatio

n, which vehicle had the greatest acceleration?

Physics
1 answer:
blagie [28]3 years ago
5 0

Answer:

Vehicle 1

Explanation:

WE know that a=F/m and since F is the same for all vehicles, it means the higher the mass, the lesser the acceleration and the smaller the mass the higher the acceleration. From the table given, vehicle a has the smallest mass, of 1000 Kg hence it yields the highest acceleration

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Which of the following statements about sidewall markings is correct? a. The load index is given as a letter. b. The traction an
vagabundo [1.1K]

Answer: all the above options are correct.

Explanation:

In sidewall markings,the load index is given as a letter,traction and temperature ratings are based on the speed rating of the tire,the tire's recommended inflation pressure and load are indicated and the DOT code indicates when and where the tire was made.

8 0
3 years ago
How much force does a soccer goalie
Tems11 [23]

Answer:

2 N

Explanation:

From the question, it's given that

Mass m = 0.2 kg

Acceleration a = 10 m/s^2

The force a soccer goalie experience when stopping a ball will be equal to the force at which the ball is being kicked. This is

F = ma

Substitute all the parameters into the formula

F = 0.2 × 10

F = 2 Newton.

3 0
3 years ago
The deepest point in the ocean is 11 km below sea level, deeper than Mt. Everest is tall.
34kurt

The pressure at the depth 11 km below sea level can be calculated using

P=ρgh

P is pressure, ρ is the density of the fluid; g is the gravitational constant, h is the height from the surface, or depth that the object is submerged.

P = ( 1000 kg/ m3) ( 9.81 m.s2)( 11 000m) + 1 atm

P = 107,910,000 pa ( 1 atm/ 101 325 Pa) + 1 atm = 1066 atm

8 0
4 years ago
Is this a testable question?
faltersainse [42]
This is a non testable question because it cannot be answered by doing an experiment. But it could be modified for example Dogs are more obedient then cats.
8 0
4 years ago
Read 2 more answers
A stone is thrown, run a velocity of 15m/s is projected of an elevation of 30° to the horizontal calculate the time rate of flig
frozen [14]

Answer:

1.53 seconds

Explanation:

Applying,

T = 2usin∅/g................ Equation 1

Where, T = time of flight, u = initial velocity, ∅ = angle of projectile to the horizontal, g = acceleration due to gravity

From the question,

Given: u = 15 m/s, ∅ = 30°

Constant: g = 9.8 m/s²

Substitute these values in equation 1

T = 2(15)(sin30°)/9.8

T = 15/9.8

T = 1.53 seconds

Hence the time rate of flight is 1.53 seconds

3 0
3 years ago
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