The students were told that the net applied force from the engine was the same for each vehicle tested. Based on this informatio
n, which vehicle had the greatest acceleration?
1 answer:
Answer:
Vehicle 1
Explanation:
WE know that a=F/m and since F is the same for all vehicles, it means the higher the mass, the lesser the acceleration and the smaller the mass the higher the acceleration. From the table given, vehicle a has the smallest mass, of 1000 Kg hence it yields the highest acceleration
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Given :
A cell of e.m.f 1.5 V and internal resistance 2.5 ohm is connected in series with an ammeter of resistance 0.5 ohm.
To Find :
The current in the circuit.
Solution :
We know, resistance of the ammeter is in series with the circuit.
So, total resistance is :
R = 2.5 + 0.5 ohm
R = 3 ohm
Also, e.m.f applied is 1.5 V .
Now, by ohm's law :
Therefore, the current in the circuit is 0.5 A.
Kepler's third law is used to determine the relationship between the orbital period of a planet and the radius of the planet.
The distance of the earth from the sun is .
<h3>What is Kepler's third law?</h3>
Kepler's Third Law states that the square of the orbital period of a planet is directly proportional to the cube of the radius of their orbits. It means that the period for a planet to orbit the Sun increases rapidly with the radius of its orbit.
Given that Mars’s orbital period T is 687 days, and Mars’s distance from the Sun R is 2.279 × 10^11 m.
By using Kepler's third law, this can be written as,
Substituting the values, we get the value of constant k for mars.
The value of constant k is the same for Earth as well, also we know that the orbital period for Earth is 365 days. So the R is calculated as given below.
Hence we can conclude that the distance of the earth from the sun is .
To know more about Kepler's third law, follow the link given below.