The combined momentum is 4000 kg m/s south
Explanation:
The total combined momentum of the two cars is given by the vector addition of the momenta of the two cars.
For this problem, we choose north as positive direction and south as negative direction.
The momentum of the first car travelling north is given by:

where
is the mass of the car
is its velocity
Substituting,

The momentum of the second car travelling south is given by:

where
is the mass of the car
is its velocity (negative because the car travels south)
Substituting,

And therefore, the combined momentum is

where the negative sign means the direction of the total momentum is south.
Learn more about momentum:
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If it is completely elastic, you can calculate the velocity of the second ball from the kinetic energy
<span>v1 = velocity of #1 </span>
<span>v1' = velocity of #1 after collision </span>
<span>v2' = velocity of #2 after collision. </span>
<span>kinetic energy: v1^2 = v1' ^2 + v2' ^2 (1/2 and m cancel out) </span>
<span>5^2 = 4.35^2 + v2' ^2 </span>
<span>v2 = 2.46 m/s <--- ANSWER</span>
Answer:
Number of turns in secondary will be 7
Explanation:
We have given primary voltage 
Number of turns in the primary is 
Secondary voltage is given 
We have to find the number of turns in secondary
We know that 
So 

As the number of turns can not be in decimal so number of turns will be 7
882 divided by 9.81 (this is acceleration due to gravity) it equals 89.91
Answer:
The gravitational potential energy of the two-sphere system just as B is released is
U = -[(G)(MA)(MB)/x₁]
where G = Gravitational constant
G = (6.7 × 10⁻¹¹) Nm²/kg²
Explanation:
The gravitational potential energy of two masses (m and M), separated by a distance, d, is given as
U = -(GMm/d)
For our question,
Mass of object 1 = MA
Mass of object 2 = MB
Distance between them = x₁
U = -[(G)(MA)(MB)/x₁]
where G = Gravitational constant
G = (6.7 × 10⁻¹¹) Nm²/kg²
Hope this Helps!!!