For the first interval (-1, 2), f(-1) = f(2), which means that the average rate of change on that interval is zero, so the correct option is A.
<h3>
Over which interval the rate of change is zero?</h3>
For a function f(x) we define the average rate of change over the interval (a, b) is defined as:
R = (f(b) - f(a))/(b - a)
Here the function is:
f(x) = x^2 - x -1
And the rate of change will be zero on an interval (a, b) if and only if:
f(b) = f(a).
Notice that the first interval is (-1, 2)
f(-1) = (-1)^2 - (-1) - 1 = 1 + 1 - 1 = 1
f(2) = 2^2 - 2 - 1 = 4 - 2 - 1 =1
Then f(-1) = f(2), which means that the average rate of change on that interval is zero, so the correct option is A.
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Answer:
$1.95 hope this helped
Step-by-step explanation:
Nope.
They don't meet the requirements of the triangle inequality.
2.1 + 4 = 6.1 < 7.9
The triangle inequality requires the sum of any two sides be greater than the third side.
Answer:
y = -3
Step-by-step explanation:
A horizontal line has all the same y values, but changing x values
y must equal -3 all the time if it goes through (3,-3)
y = -3
Answer:
one side = 
Step-by-step explanation:
if you draw an octagon on a piece of paper, you can draw a square around it, you should be able to see a diagram of this attached, ignore the 6.
Let's say TP = a
since it's a regular octagon, TP = HT
and using the Pythagoras Theorem, we know a² + b² = c² and thus:
√(AT² + HA²) = HT
and since AT = HA which we will call x, the equation becomes:
√(2x²) = HT = a
rearrange the equation to solve for x and you get:
2x² = a²
x² = 
x = 
which, if you rationalise the denominator, you get:
x =
