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siniylev [52]
3 years ago
13

In ΔHIJ, the measure of ∠J=90°, HI = 6.7 feet, and JH = 4.8 feet. Find the measure of ∠I to the nearest degree.

Mathematics
1 answer:
Readme [11.4K]3 years ago
3 0

Answer:

46

Step-by-step explanation:

Sin(4.8/6.7)=45.7596=46

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It is 1595. Put it on excel so you can better have an overview how it is done. You need 5 columns, column A-E. On column A, put 1 to 5 in rows 1 to 5. On column C, put the answers: 2, 7, 26, 101 and 400. On column D, put number 3 in all 5 rows. Back on column B, insert =sum(C1-A1) on row 1 and copy till row 5. On column E, insert =sum(B1+C1*D1) on row 1 and copy till row 5 and you will get 1595 at the end.
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3.5 is what percent of 7.15
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48.95 percent (rounded)

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Point Y is the circumcenter of triangle DEF.
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Please show your work I will mark you Brainiest
Talja [164]

Answer:

1. 7

2. 5/8

3. 5

4. 20

Step-by-step explanation:

There is one burger that weighs 3/8 pounds, four that weigh 1/2 pound, and two that weigh 3/4 pounds. The difference between the heaviest and the lightest is 3/4-1/8=5/8. The total combined weight is 5 pounds. 5/ 1/4= 5*4=20. Hope this helps!

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) find a vector parallel to the line of intersection of the planes 5x − y − 6z = 0 and x + y + z = 1.
snow_tiger [21]
The cross product of the normal vectors of two planes result in a vector parallel to the line of intersection of the two planes.

Corresponding normal vectors of the planes are
<5,-1,-6> and <1,1,1>

We calculate the cross product as a determinant of (i,j,k) and the normal products

    i   j   k
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   1  1  1

=(-1*1-(-6)*1)i -(5*1-(-6)1)j+(5*1-(-1*1))k
=5i-11j+6k
=<5,-11,6>

Check orthogonality with normal vectors using scalar products
(should equal zero if orthogonal)
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Therefore <5,-11,6> is a vector parallel to the line of intersection of the two given planes.
5 0
3 years ago
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