The definition of a circle uses the undefined term? ..

Ali bought 2.152.15 pounds of turkey at $7.89$7.89 per pound, and 1.871.87 pounds of lamb at $7.89$7.89 per pound. Which express

Stella [2.4K]

In order to calculate the total cost of the purchase, we must first assess that there were two items bought, turkey and lamb. Next, we see multiply the cost of the first item by its quantity, so:
cost(T) = 2.15 * 7.89
cost(T) = $16.96
And repeat for the second item:
cost(L) = 1.87 * 7.89
cost (L) = $14.75

Finally, the total cost is the sum of these costs. So
Total = 16.96 + 14.75
Total = $31.71

6 0

3 years ago

Read 2 more answers

A company claims that less than 10% of adults own a smart watch. You want to test this claim, and you find that in a random samp

Nezavi [6.7K]

Answer:

Test statistic is 0.67

Critical value is -2.33

Step-by-step explanation:

Consider the provided information.

The formula for testing a proportion is based on the z statistic.

$z=\frac{\hat p-p_0}{\sqrt{p_0\frac{1-p_0}{n}}}$

Were $\hat p$ is sample proportion.

$p_0$ hypothesized proportion and n is the smaple space,

Random sample of 100 adults, 12% say that they own a smart watch.

A company claims that less than 10% of adults own a smart watch.

Therefore, n = 100 $\hat p$ = 0.12 , $P_0$ = 0.10

$1 - P_0 = 1 - 0.10 = 0.90$

Substitute the respective values in the above formula.

$z=\frac{0.12-0.10}{\sqrt{0.10\frac{0.90}{100}}}$

$z\approx 0.67$

Hence, test statistic = 0.67

This is the left tailed test.

Now using the table the P value is:

P(z < 0.667) = 0.7476

P-value = 0.7476

$\alpha = 0.01$

Here, P-value > α therefore, we are fail to reject the null hypothesis.

$Z_{\alpha}= Z_{0.01} = -2.33$

Hence, Critical value is -2.33

7 0

3 years ago

HELP! Which graph best represents the equation shown below? 8x + 5y = 1

777dan777 [17]

Answer:

The answer is graph A. 8x +5y =1 can be rewritten as y =(1 - 8x)/5

8 0

3 years ago

A fair 6-faced die is tossed twice. Letting E and F represent the outcomes of the each toss (which are independent), compute the

andreyandreev [35.5K]

Answer:

(a) $\frac{1}{18}$ (d) $\frac{1}{9}$

(b) $\frac{1}{2}$ (e) $\frac{1}{3}$

(c) $\frac{4}{9}$ (f) $\frac{1}{12}$

Step-by-step explanation:

On tossing a 6-face die twice the outcomes of E and F are:

{1, 2, 3, 4, 5 and 6}

And there are total 36 outcomes of the form (E, F).

(a)

The sample space of getting a sum of 11 is: {(5, 6) and (6, 5)}

The probability of getting a sum of 11 is:

$P(Sum 11) =\frac{2}{36} \\=\frac{1}{18}$

(b)

The sample space of getting an even sum is:

{(1, 1), (1, 3), (1, 5), (2, 2), (2, 4), (2, 6) (3, 1), (3, 3), (3, 5), (4, 2), (4, 4), (4, 6) (5, 1), (5, 3), (5, 5), (6, 2), (6, 4), (6, 6)}

The probability of getting an even sum is:

$P(Even Sum)=\frac{18}{36}\\ =\frac{1}{2}$

(c)

The sample space of getting an odd sum more than 3 is:

{(1, 4), (1, 6), (2, 3), (2, 5), (3, 2), (3, 4), (3, 6), (4, 1), (4, 3), (4, 5), (5, 2), (5, 4), (5, 6), (6, 1), (6, 3) and (6, 5)}

The probability of getting an odd sum more than 3 is:

P (Odd Sum more than 3) =

$=\frac{16}{36}\\=\frac{4}{9}$

(d)

The sample space of (E, F) such that E is even and less than 6, and F is odd and greater than 1 is:

{(2, 3), (2, 5), (4, 3) and (4, 5)}

The probability such that E is even and less than 6, and F is odd and greater than 1 is:

$P(Even E1) =\frac{4}{36} \\=\frac{1}{9}$

(e)

The sample space of E and F such that E is more than 2, and F is less than 4 is:

E = {3, 4, 5 and 6} F = {1, 2 and 3}

Then the total outcomes of (E, F) will be 12.

The probability such that E is more than 2, and F is less than 4 is:

$P(E>2, F$

(f)

The sample space of (E, F) such that E is 4 and sum of E and F is odd is:

{(4, 1), (4, 3) and (4, 5)}

The probability such that E is 4 and sum of E and F is odd is:

$P(E=4, E+F = Odd)=\frac{3}{36} \\=\frac{1}{12}$

6 0

3 years ago

CAN SOMEONE PLEASE HELP MEEEE!!!!

pantera1 [17]

Question:

In triangle JKL, the measure of angle L = 90°, KJ = 37, LK = 12, and JL = 35. What ratio represents the cosine of angle J?

__________________________________________________

Solution:

The triangle JKL should look like that in the attachment.

Cosine of J = adjacent side/hypotenuse

= LJ/KJ

= 35/37

7 0

3 years ago