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34kurt
3 years ago
12

Math help please... i will be marking brainly

Mathematics
1 answer:
TiliK225 [7]3 years ago
8 0

Answer:

A polynomial needs to have either addition, subtraction or multiplication in the equation.

The 2nd, 3rd and 4th answers have subtraction and addition, so those are polynomials.


The first answer is a fraction, which is a division problem, therefore is not a polynomial.


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WILL MARK BRAINLIEST!!!!!! AND 20 POINTS!!!!!!
defon

you didn't include the graph

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3 years ago
Select the correct answer.
wariber [46]

Answer:

<u>~Senpi boi here~</u>

Step-by-step explanation:

Multiply all terms by x and cancel:

x+2x+1=1x

3x+1=x(Simplify both sides of the equation)

3x+1−x=x−x(Subtract x from both sides)

2x+1=0

2x+1−1=0−1(Subtract 1 from both sides)

2x=−1

2x

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=

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(Divide both sides by 2)

x=

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Check answers. (Plug them in to make sure they work.)

x=

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(Works in original equation)

<u>Answer:</u>

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5 0
1 year ago
Consider the system of differential equations dxdt=−4ydydt=−4x. Convert this system to a second order differential equation in y
koban [17]

\dfrac{\mathrm dy}{\mathrm dt}=-4x\implies x=-\dfrac14\dfrac{\mathrm dy}{\mathrm dt}\implies\dfrac{\mathrm dx}{\mathrm dt}=-\dfrac14\dfrac{\mathrm d^2y}{\mathrm dt^2}

Substituting this into the other ODE gives

-\dfrac14\dfrac{\mathrm d^2y}{\mathrm dt^2}=-4y\implies y''-16y=0

Since x(t)=-\dfrac14y'(t), it follows that x(0)=-\dfrac14y'(0)=4\implies y'(0)=-16. The ODE in y has characteristic equation

r^2-16=0

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y_c=C_1e^{4t}+C_2e^{-4t}

From the initial conditions we get

y(0)=5\implies 5=C_1+C_2

y'(0)=16\implies-16=4C_1-4C_2

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So we have

\boxed{y(t)=\dfrac12e^{4t}+\dfrac92e^{-4t}}

Take the derivative and multiply it by -1/4 to get the solution for x(t):

-\dfrac14y'(t)=\boxed{x(t)=-\dfrac12e^{4t}+\dfrac92e^{-4t}}

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3 years ago
Please help me with this homework
Akimi4 [234]

Answer:

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Step-by-step explanation:

Tell me in the comments if I'm wrong.

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2 years ago
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Amiraneli [1.4K]

Answer:

0.101

Step-by-step explanation:

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