The diagonals of a parallelogram are congruent
The length WY is 32
<h3>How to determine the length WY</h3>Given that:
and
Then, we have:
diagonal
Subtract x^2 from both sides
Divide both sides by -6
The length WY is calculated as:
So, we have:
Substitute 8 for x
Simplify
Hence, the length WY is 32
Read more about parallelograms at:
Answer:
11. (x-2)/(x+8)
12. 9+t
13. h = 2A/b
Step-by-step explanation:
11. Since x is used to represent the number, 2 less than a number is x-2. 8 more than a number is x+8. The quotient of the first and second of these is the first one divided by the second one:
... (x -2)/(x +8) . . . . . parentheses are required unless the expression is typeset:
12. Apparently, we're to assume the salesman keeps on driving. If he had any sense (or a good union), he would stop after 9 hours. t hours added to 9 is ...
... 9 + t
13. Divide by the coefficient of h.
... h = A/((1/2)b) = 2A/b
Step-by-step explanation:
1. First figure
We plot the parabola as given in the attached diagram.
As it is facing upwards, the equation goes as x² = 4py
where, p = 4 (refer the attached diagram)
x² = 4py
x² = 4 (4) y
∴, standard form of parabola is x² = 16 y
2. Second figure
(y + 3)² = 4 (x - 1)
Comparing the given equation with the standard form
(y - k)² = 4p (x - h)
Now from this equation we get to know that
h = 1
p = 1
Directrix is x = (h - p)
So, x = 0
3. Third figure
3x² + 24x - 2y + 52 = 0
3x² + 24x = 2y - 52
3 (x² + 8x) = 2 (y - 26)
(x² + 8x) = 2 (y - 26) / 3
Adding 16 on both sides,
x² + 8x + 16 = 2 (y - 26) / 3 + 16
(x + 4)² = 2/3 y - 52/3 + 16
(x + 4)² = 2/3 y - 4/3
(x + 4)² = 2/3 (y - 2)
4. Fourth figure
(y + 1)² = 12 (x - 3)
Comparing the given equation with the standard form
(y - k)² = 4p (x - h)
Now from this equation we get to know that
k = -1
h = 3
p = 3
Gayle identifies that the vertex of the parabola is <u>(3, -1)</u> . The parabola opens <u>right</u>, and the focus is <u>3 </u>units away from the vertex. The directrix is <u>6 </u>units from the focus. The focus is the point <u>(6, -1)</u>. The directrix of the equation is <u>x = 0.</u>
5. Fifth figure
Focus = (2, 6)
Directrix is x = 4
Therefore, it follows the standard form
(y - k)² = 4p (x - h)
Directrix is given by x = h-p = 4
Focus is given by (h + p, k) = (2, 6)
Solving for (h - p) = 4, (h + p) = 2
2 - p - p = 4
-2p = 2
p = -1
Hence, h = 3
Therefore, the standard form can be written as
(y - 6)² = 4p (x - 3)
