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Vesna [10]
3 years ago
9

What is the product? -9x(5-2x) 2

Mathematics
1 answer:
fiasKO [112]3 years ago
6 0

-9x(5-2x)

What does the second two mean?

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Can someone help me ASAP
sammy [17]

Answer:

8/9 n-3

Step-by-step explanation:

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3 years ago
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The varlables x and y vary Inversely. Use the given values to wrke an equation relating X and y
ZanzabumX [31]
X and y vary inversely means y is inversely proportional to x, this means:

y=k/x, where k is a constant.

We are given that when x=-4, y=7/2, we replace these values to find k.

7/2=k/-4
k= (-4*7)/2=-14

So we have y=-14/x

Therefore, when x=4, y=-14/4= -7/2
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Please help me my moms gonna kill me if I don’t get this done(20 points)
Nutka1998 [239]

Answer:

x=30° y=4

Step-by-step explanation:

\frac{y}{8}  =  \frac{2.5}{5}

cross multiple

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Help which answer choice, when multiplied, would give the inverse of
OleMash [197]
The answer is b. Because it just is
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2 years ago
Expand ( x - 1/x^2)^4
emmainna [20.7K]

Answer:

We want to expand the expression:

(x - \frac{1}{x^2} )^4

We can just do it by brute force, this is:

First, rewrite our expression as the product of two square factors:

(x - \frac{1}{x^2} )^4 = (x - \frac{1}{x^2} )^2*(x - \frac{1}{x^2} )^2

Now we can expand each one these two factors:

(x - \frac{1}{x^2} )^2 = (x - \frac{1}{x^2} )*(x - \frac{1}{x^2} ) = x^2 + \frac{1}{x^4} -2*x*\frac{1}{x^2}

That can be simplified to

x^2 - \frac{2}{x} + \frac{1}{x^4}

Now we can replace that in our original expression to get:

(x^2 - \frac{2}{x} + \frac{1}{x^4})*(x^2 - \frac{2}{x} + \frac{1}{x^4})

Now we can expand that last product, to get:

(x^2)^2 + 2*(x^2)*(-\frac{2}{x} ) + 2*(x^2)*(\frac{1}{x^4}) + 2*(\frac{-2}{x})*(\frac{1}{x^4}) + (\frac{-2}{x}  )^2 + (\frac{1}{x^4})^2

We can simplify that to:

x^4 - 4x + 2x^2 - \frac{4}{x^5}  + \frac{4}{x^2} + \frac{1}{x^8}

That is the expanded expression.

6 0
3 years ago
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