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3 years ago

Pls help for this pre calc question 25 points rewarded!

Mathematics

1 answer:

Temka [501]3 years ago

3 0

Let's check the dot product .

v.w = 5(4)-2(10) = 20 -20 =0

So the dot product is not 20 . And since the dot product is zero, so they are perpendicular.

And the y component of w is 10.

So correct options are first and third .

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Choose the equation below that represents the line passing through the point (−2, −3) with a slope of −6.

lubasha [3.4K]

Y = mx + b
slope(m) = -6
(-2,-3)...x = -2 and y = -3
now we sub....we r looking for b, the y int
-3 = -6(-2) + b
-3 = 12 + b
-3-12 = b
-15 = b

so ur equation is : y = -6x - 15

7 0

3 years ago

javier rode his bike for a total of 41 minutes. before lunch he rode 1 minute less than 5 times the number of minutes he rode af

notka56 [123]

Answer:

Javier rode bike 34 minutes before lunch.

Step-by-step explanation:

Let the number of minutes Javier rode the bike after lunch be = x minutes

Then according to question number of minutes he rode the bike after lunch

$= 5x-1$

Total number of minutes he rode bike = 41 min

Therefore,

$x+5x-1 =41$

On solving

$6x= 41+1 =42$

Divide both side by 6 we get

$x= 7$

Number of minutes he ride before lunch

$= 5(7)-1 = 35-1=34$ min

8 0

3 years ago

Y + (-3 y2 ) +2( y2 - 6y) simplify

labwork [276]

Answer:

y - 3y^2 + 4y^2 - 12y

y^2 - 11y

Step-by-step explanation:

3 0

2 years ago

Given that f.x 3x-2 over x+1 g[x] x +5 evaluate f[-4] and gf [-2]

Jobisdone [24]

The value of f[ -4 ] and g°f[-2] are $\frac{14}{3}$ and 13 respectively.

<h3>What is the value of f[-4] and g°f[-2]?</h3>

Given the function;

$f(x) = \frac{3x-2}{x+1}$
$g(x)=x+5$
f[ -4 ] = ?
g°f[ -2 ] = ?

For f[ -4 ], we substitute -4 for every variable x in the function.

$f(x) = \frac{3x-2}{x+1}\\\\f(-4) = \frac{3(-4)-2}{(-4)+1}\\\\f(-4) = \frac{-12-2}{-4+1}\\\\f(-4) = \frac{-14}{-3}\\\\f(-4) = \frac{14}{3}$

For g°f[-2]

g°f[-2] is expressed as g(f(-2))

$g(\frac{3x-2}{x+1}) = (\frac{3x-2}{x+1}) + 5\\\\g(\frac{3x-2}{x+1}) = \frac{3x-2}{x+1} + \frac{5(x+1)}{x+1}\\\\g(\frac{3x-2}{x+1}) = \frac{3x-2+5(x+1)}{x+1}\\\\g(\frac{3x-2}{x+1}) = \frac{8x+3}{x+1}\\\\We\ substitute \ in \ [-2] \\\\g(\frac{3x-2}{x+1}) = \frac{8(-2)+3}{(-2)+1}\\\\g(\frac{3x-2}{x+1}) = \frac{-16+3}{-2+1}\\\\g(\frac{3x-2}{x+1}) = \frac{-13}{-1}\\\\g(\frac{3x-2}{x+1}) = 13$

Therefore, the value of f[ -4 ] and g°f[-2] are $\frac{14}{3}$ and 13 respectively.

Learn more about composite functions here: brainly.com/question/20379727

#SPJ1

6 0

1 year ago

Answers for these? Having trouble getting the concept so a step by step would be awesome.

jolli1 [7]

Answer: 2222

Step-by-step explanation: 2000+200+20+2 = 2222

6 0

3 years ago

Read 2 more answers