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laila [671]
4 years ago
15

plant A is 18 inches tall after one week 36 inches tall after two weeks 56 inches tall after three weeks plant B is 18 inches ta

ll after one week 36 inches tall after two weeks 54 inches tall after three weeks which situation represensts a proportional relationship between the plants height and number of weeks
Mathematics
1 answer:
Afina-wow [57]4 years ago
3 0
Plants increase by 18 inches every week
proportion would be 18inches/week
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A diver dives from a 10m springboard. the equation f(t) = -4.9t² + 4t + 10 models her height above the pool at time t. When will
Gennadij [26K]

Answer:

At time t = 0.408 sec diver will be at maximum height

Step-by-step explanation:

We have given equation of the height f(t)=-4.9t^2+4t+9

We know that velocity is the rate of change of distance with respect to time

So v=\frac{df(t)}{dt}=\frac{df(-4.9t^2+4t+10)}{dt}=-9.8t+4+0=-9.8t+4

At maximum height velocity will be zero

So -9.8t+4=0

t = 0.408 sec

So at time t = 0.408 sec diver will be at maximum height

5 0
3 years ago
Standard form for 4 hundred-thousands,13 thousands,11 hundreds, 4 ones
Stells [14]
413,114
btw there cant be 11 hundreds or 13 thousands
so its this
5 0
3 years ago
The .............. from the regular selling price to the discounted sale price is 20%
11Alexandr11 [23.1K]

Answer:

80%

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regular price is 100%

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4 0
3 years ago
Please help me.<br><br>List the sides of MNP in ascending order:<br>m&lt; M = 15, m &lt; N= 75
oksian1 [2.3K]

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Take a look at this: brainly.com/question/14269575?referrer=searchResults

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6 0
3 years ago
Albert wants to show that tan(theta)sin(theta)+cos(theta)=sec(theta). He writes the following proof:
Nataly_w [17]
We have that
<span>tan(theta)sin(theta)+cos(theta)=sec(theta)
</span><span>[sin(theta)/cos(theta)] sin(theta)+cos(theta)=sec(theta)
</span>[sin²<span>(theta)/cos(theta)]+cos(theta)=sec(theta)

</span><span>the next step in this proof
is </span>write cos(theta)=cos²<span>(theta)/cos(theta) to find a common denominator
so

</span>[sin²(theta)/cos(theta)]+[cos²(theta)/cos(theta)]=sec(theta)<span>

</span>{[sin²(theta)+cos²(theta)]/cos(theta)}=sec(theta)<span>

remember that 
</span>sin²(theta)+cos²(theta)=1
{[sin²(theta)+cos²(theta)]/cos(theta)}------------> 1/cos(theta)
and 
1/cos(theta)=sec(theta)-------------> is ok

the answer is the option <span>B.)
He should write cos(theta)=cos^2(theta)/cos(theta) to find a common denominator.</span>
6 0
3 years ago
Read 2 more answers
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