2,250 m from his starting point.
Just turn 3.5 into 3500.
Then subtract 3500 by 1250. And the tiger ran 2250 m.
Answer:
The dimension of the play area written algebraically is y²/2 + 9y
Step-by-step explanation:
Let the be x and the width be y
If the length is to be 9 feet longer than half the width,
hence y/2 + 9 = x
hence dimension of the area = (y/2 + 9) × y = y²/2 + 9y
Answer:
Parallel
<u>Step-By-Step Explanation:</u>
Put the Function in Slope Intercept Form and Find the Slope of 6x+3y = 15
6x+3y = 15
3y = -6x + 15
3y/3 = -6x/3 + 15/3
y = -2x + 5
<u>We can see that the slope of 6x+3y = 15 is -2</u>
Put the Function in Slope Intercept Form and Find the Slope of y–3=–2x
y–3=–2x
y = -2x + 3
Here are our two Functions In Slope Intercept Form
y = -2x + 5
y = -2x + 3
<u>Remember the m = slope and the b = y-intercept</u>
y = mx + b
y = -2x + 5
y = -2x + 3
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We can see both equations have the same slope of -2 so this means they could be parallel because parallel functions have the same slope but coinciding functions have the same slope too. To tell if the two functions are coinciding, the functions need to have the same slope and the same y-intercept. Looking at the two functions, we can see they have the same slope of -2 but their y-intercept are different so this makes the two functions parallel.
P=2 then 2^2+4=8
P=11 then 11^2+4=125
