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Nataliya [291]
3 years ago
7

It’s due tomorrow plz HELP

Mathematics
1 answer:
Vikentia [17]3 years ago
7 0

1)

\dfrac{3}{4}  + 5 -  \dfrac{1}{2}  = \dfrac{3}{4}  +  \dfrac{20}{4} -  \dfrac{2}{4}  =  \dfrac{21}{4}  = 5 \dfrac{1}{4}

2)

\dfrac{2}{3}  +  {2}^{3}  -  \dfrac{1}{3}  =  \dfrac{2}{3}  +  \dfrac{24}{3}  -  \dfrac{1}{3}  =  \dfrac{25}{3}  = 8 \dfrac{1}{3}

3)

- 15 + 6x - 19 - 20x =  - 14x - 34

4)

- 7x - 2 - 9y + 10x = 3x - 9y - 2

5)

14 + x = 18 \\ x = 18 - 14 \\ x = 4

6)

- 5x =  - 15 \\ x =  - 15 \div ( - 5) \\ x = 3

7)

- 2x + 8 = 18 \\  - 2x = 18 - 8 \\  - 2x = 10 \\ x = 10 \div ( - 2) \\ x =  - 5

8)

3x + 18 - 8x =  - 17 \\ 3x - 8x =  - 17 - 18 \\  - 5x =  - 35 \\ x =  - 35 \div ( - 5) \\ x = 7

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sveticcg [70]

Answer:

The correct option is;

W

Step-by-step explanation:

The number of points that defines a plane in a Euclidean space in all dimensions is either three points which are not on the same line, or two colinear points and a third point not on the line

The given points of the plane are UVX, which gives the plane as being diagonal to the cube and perpendicular to the side face of the cube.

The fourth point in plane UVX is therefore W.

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Let me know the answer plz
Gala2k [10]

<u>Answer:</u>

The correct answer option is H. 4374.

<u>Step-by-step explanation:</u>

We are given the following geometric sequence and we are to find its 8th term:

\frac{2}{9}, \frac{2}{3}, 2,...

Here a_1=\frac{2}{9} and common ratio (r) = \frac{\frac{2}{3} }{\frac{2}{9} } =3.

The formula we will use to find the 10th term is:

nth term = a_1 \times r^{(n-1)}

Substituting the values in the formula to get:

10th term = \frac{2}{9} \times 3^{(10-1)}

10th term = 4374

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3 years ago
Tarin organized this table to determine the number of adults a and children attending a fundraiser based on the total number of
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F(x)=|3x+5|+6<br> g(x)=7<br> find (f+g) (x).
horrorfan [7]

Answer:

(f+g) (x)=\mid 3x+5\mid+13

Step-by-step explanation:

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Given:

f(x)=\mid 3x+5\mid+6

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The sum of (f+g) (x) is:

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\boxed{(f+g) (x)=\mid 3x+5\mid+13}

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