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Nataliya [291]
3 years ago
8

. 7 prizes are to be distributed between 3 people with a guarantee that each person gets at least one prize. Find the number of

ways the prizes can be distributed.
Mathematics
1 answer:
ANEK [815]3 years ago
7 0

Answer:

Total number of ways to distribute the prize = 2187

3^{7}= 2187

Step-by-step explanation:

Given:

Number of prizes = 7

Number of peoples = 3

We need to find the total number of ways to distribute the prize.

Solution:

From the above statement, 7 prizes are to be distributed between 3 people, wherein each person gets at least one prize.

Each prize is to be distributed among three persons. When the first prize is to be awarded, one of the three is chosen to win the prize. When the second prize is to be awarded, there are again three choices.

So, total number of distribution of the prizes is given as:

3\times 3 \times 3\times 3\times 3\times 3\times 3=3^{7}

3^{7}= 2187

Therefore, total number of ways to distribute the prizes = 2187

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Step-by-step explanation:

Ir order to perform the implicit differentiation, you have to differentiate with respect to x. Then, you have to use the conditions for horizontal and vertical tangent lines.

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\frac{d(x^{2}-2xy+y^{2}+4x-8y+20)}{dx} = \frac{d(x^{2})}{dx}-2\frac{d(xy)}{dx}+\frac{d(y^{2})}{dx}+4\frac{dx}{dx}-8\frac{dy}{dx}+\frac{d(20)}{dx}=2x -2(y+x\frac{dy}{dx})+2y\frac{dy}{dx}+4-8\frac{dy}{dx}= 0

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\frac{2y-2x-4}{2y-2x-8}=0\\2y-2x-4=0

Solving for y (Adding 2x+4, dividing by 2)

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Replacing (I) in the given equation:

x^{2}-2x(x+2)+(x+2)^{2}+4x-8(x+2)+20=0\\x^{2}-2x^{2}-4x+x^{2} +4x+4+4x-8x-16+20=0\\-4x+8=0\\x=2

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Therefore, the parabola has a horizontal tangent line at the point (2,4)

Applying the second condition (slope is undefined where denominator is zero)

2y-2x-8=0

Adding 2x+8 both sides and dividing by 2:

y=x+4(II)

Replacing (II) in the given equation:

x^{2}-2x(x+4)+(x+4)^{2}+4x-8(x+4)+20=0\\x^{2}-2x^{2}-8x+x^{2}+8x+16+4x-8x-32+20=0\\-4x+4=0\\x=1

Replacing it in (II)

y=1+4

y=5

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