Complete Question
Although the first quarter of 2002 was quite dismal on Wall Street, mutual funds investing in gold companies rose an average of 35.2%. Assume that the distribution of returns in the first quarter of 2002 for mutual funds specializing in gold companies is fairly symmetrical with a mean of 35.2% and a standard deviation of 20%. If random samples of 16 gold stock funds were selected:
90% of the sample mean returns are between what two values symmetrically distributed around the mean?
Answer:
The two values symmetrically distributed around the mean are
21.87\% and 43.17\%
Step-by-step explanation:
From the question we are told that
The sample size is ![n = 16](https://tex.z-dn.net/?f=n%20%3D%2016)
The sample mean is ![\= x = 0.352](https://tex.z-dn.net/?f=%5C%3D%20x%20%20%3D%20%200.352)
The standard deviation is ![\sigma = 0.20](https://tex.z-dn.net/?f=%5Csigma%20%3D%20%200.20)
Generally the degree of freedom is mathematically represented as
![df = n -1](https://tex.z-dn.net/?f=df%20%3D%20n%20-1)
=> ![df = 16 -1](https://tex.z-dn.net/?f=df%20%3D%2016%20-1)
=> ![df = 15](https://tex.z-dn.net/?f=df%20%3D%2015)
From the question we are told the confidence level is 90% , hence the level of significance is
=>
Generally from the t distribution table the critical value of
at a degree of freedom of
is
Generally the margin of error is mathematically represented as
=>
=>
Generally 90% confidence interval is mathematically represented as
=>
converting to percentage
=>
Hence the 90% of the sample mean returns are between 21.87\% and 43.17\%
Since there is a ratio of 3:2, there must be five equal parts in the whole...
45/(3+2)=9
So each part is equal to 9 inches.
So the shorter piece is 2(9)=18 inches.
Answer:
42 square feet
Step-by-step explanation:
10 ×3= 30
4×3=12 divided by two =6 ×2= 12
(multiply because there are two triangular ends)
12+30=42
The answer is one third or 1/3 multiply diagonal both ways and then multiply denominators