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LekaFEV [45]
3 years ago
11

In the broken china plate, CD = 8 cm, OY, the perpendicular bisector of CD, = 3 cm. What is the diameter of the plate?

Mathematics
2 answers:
jekas [21]3 years ago
7 0

Answer:

Step-by-step explanation:

taking this one step further, since the radius is 5 cm, the diameter is 10 cm.

the answer to the question is 10.

KengaRu [80]3 years ago
6 0
I hope this helps you

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10.125 as a percentage is 1012.5%

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What is the value of -16 divided by 2.5
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Hey the answer to your question is -6.4
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2 years ago
Please help me I’m super confused on this problem!
Lorico [155]

Answer:

m < amc = 54°

Step-by-step explanation:

< amb and < bmc are complementary angles whose sum equals 90°.

Therefore, to find the value of 2x°, we must first solve for x.

We can establish the following equality statement:

< amb + < bmc = < amc

< 2x° + (x + 9)° = 90°

Combine like terms:

2x° + x° + 9° = 90°

3x° + 9° = 90°

Subtract 9 from both sides:

3x° + 9° - 9° = 90° - 9°

3x = 81°

Divide both sides by 3 to solve for x:

3x/3 = 81°/3

x = 27°.

Since x = 27°, substitute its value into 2x° to find m < amc:

2x° = 2(27°) = 54°

Therefore, m < amc = 54°

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5 0
2 years ago
4,400 X 400 = ( blank hundreds) X ( blank hundreds) = 176 hundreds, thousands, hundrenths, tenths, tens, ones, thousands, or tho
kiruha [24]
Hello There!

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5 0
3 years ago
The school that DeShawn goes to is selling tickets to the annual dance competition. On the first day of ticket sales, the school
coldgirl [10]

Answer:

Both child tickets and senior tickets cost $14.

Step-by-step explanation:

Since the school that DeShawn goes to is selling tickets to the annual dance competition, and on the first day of ticket sales, the school sold 10 senior citizen tickets and 8 child tickets for a total of $ 252, while the school took in $ 280 on the second day by selling 10 senior citizen tickets and 10 child tickets, to determine what is the price of each of one senior citizen ticket and one child ticket, the following calculation must be performed:

10 senior tickets + 8 child tickets = 252

10 senior tickets + 10 child tickets = 280

280 - 252 = 2 child tickets

28 = 2 child tickets

28/2 = 1 child ticket

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(280 - 140) / 10 = senior tickets

140/10 = 14 = senior tickets

Therefore, both child tickets and senior tickets cost $14.

3 0
3 years ago
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