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3 years ago

Can someone help me on 64 67 68 and if you do you will get a lot of points

Mathematics

1 answer:

andre [41]3 years ago

8 0

Answer: #64, A. #67, A. #68, C

Step-by-step explanation:

#64

0.96/6= 0.16

2.4/16= 0.15

32= 0.18

16 oz is the least

#67

100/20=5

3*5=15

SO, it's 15%.

#68

Divide

$430/43= $10

$594/54= $11

Andrew= $8

So, Darren makes the most.

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Can someone check my answers to see if they're correct?

Sati [7]

Answer:

a = 125°

b = 55°

c = 55°

d = 55°

e = 125°

f = 55°

Step-by-step explanation:

See the attached diagram.

The angles (x + 75)° and (2x + 25)° are the alternate angles and they are equal.

So, x + 75 = 2x + 25

⇒ x = 50

Hence, (x + 75)° = (50 + 75)° = 125°.

Now, from the given diagram it is clear that

a = (x + 75)° = (2x + 25)° = e = 125°

And, b = c = d = f = 55°

This is because, a and b are supplementary angles and their sum will be 180°.

So, a + b = 180°

⇒ 125° + b = 180°

⇒ b = 55°

So, b = c = d = f = 55° (Answer)

3 0

2 years ago

An art student uses a roll wallpaper to decorate two gift boxes. The student will use 1 1/3 yards of paper for one box and 5/6 y

Oduvanchick [21]

The answer will 1 4/6 or (10/6) yards of wallpaper

6 0

2 years ago

What is the answer 2,700x1/10

babymother [125]

Answer:

270

Step-by-step explanation:

Note that 1/10 is equal to 0.1

Multiply 2700 with 0.1

2700 x 0.1 = 270

270 is your answer.

3 0

3 years ago

Read 2 more answers

CAN SOMEONE ANSWER THIS PLEASE THANK U LOVE U

Vanyuwa [196]

Answer:

Step-by-step explanation:

4 0

2 years ago

Read 2 more answers

During a manufacturing process, a metal part in a machine is exposed to varying temperature conditions. The manufacturer of the

mars1129 [50]

Answer:

Yes, it will reach or exceed 141 degree F

Step-by-step explanation:

Given equation that shows the temperature T in degrees Fahrenheit x minutes after the machine is put into operation is,

$T = 0.005x^2 + 0.45x + 125$

Suppose T = 141°F,

$\implies 141 = 0.005x^2 + 0.45x + 125$

$\implies 0.005x^2 + 0.45x + 125 - 141 =0$

$\implies 0.005x^2 + 0.45x - 16=0$

Since, a quadratic equation $ax^2 + bx + c =0$ has,

Real roots,

If Discriminant, $D = b^2 - 4ac \geq 0$

Imaginary roots,

If D < 0,

Since, $0.45^2 - 4\times 0.005\times -16 = 0.2025 + 32 > 0$

Thus, roots of -0.005x² + 0.45x + 125 are real.

Hence, the temperature can reach or exceed 141 degree F.

6 0

3 years ago