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erastovalidia [21]
3 years ago
12

What is the value of -5(m - 2) when m = -1

Mathematics
1 answer:
Lana71 [14]3 years ago
7 0
-5(-1-2)
5+10
15

Or

-5(-1-2)
-5(-3)
15

It's 15 either way.
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How do i figure out the degrees?
liraira [26]

Answer:

  41°

Step-by-step explanation:

This problem involving the Law of Cosines has been mostly worked for you. The value of the cosine is the solution to the remaining one-step linear equation. The inverse cosine function (cos⁻¹ or arccos) is used to find the angle from the value of the cosine.

  -1125 = -1500·cos(A)

  cos(A) = -1125/-1500 = 3/4 . . . . . divide by -1500 (this is the one step)

  A = arccos(3/4) ≈ 41.4096°

The angle formed by the lines to the lampposts is about 41°.

__

<em>Additional comment</em>

If you find the angle using the ACOS( ) function of a spreadsheet, you will always get the result in radians. Most calculators offer the choice of units for angles, so be sure you set the mode appropriately.

In the calculator screenshot, there is a decimal point in the fraction to force the angle result to be displayed as a numerical value. Otherwise, this calculator shows cos⁻¹(3/4), which isn't terribly helpful.

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2 years ago
1. Consider the surface area of the following pyramid.
Dahasolnce [82]

Answer:

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Step-by-step explanation:

6 0
3 years ago
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Stacey rolls a number cube and flips a coin. what is the probability that she rolls a 5 and the coin lands heads up?
Illusion [34]

Answer:

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4 years ago
If cos (50 degrees) = a, express tan (130 degrees) in terms of a.
Paladinen [302]

Answer: The tan 130° is expressed as \dfrac{\sqrt{1-a^2}}{a}

Step-by-step explanation:

Since we have given that

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As we know that

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So, tan 130° is given by

\dfrac{\sin 130^\circ}{\cos 130^\circ}\\\\=\dfrac{\sqrt{1-a^2}}{a}

Hence, the tan 130° is expressed as \dfrac{\sqrt{1-a^2}}{a}

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