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Iteru [2.4K]
3 years ago
11

A boat travels 32 miles on 4 gallons of fuel. How many miles per half gallon is that?

Mathematics
2 answers:
nikklg [1K]3 years ago
5 0
That would be 4 miles per half gallon.

If you do the math, 32/4 = 8. So, 1 gallon = 8. 
8 * (1/2) = 4. SO it is 4.

Hope that helps.
nasty-shy [4]3 years ago
4 0
32 divided by 4 is 8. so 8 miles per gallon.

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Nivyana and Ana are selling their apparel to earn money for a cruise. Knitted scarves are $50 each in Mittens are $25 per pair.
Katarina [22]

Answer:

The number of knitted scarves is 10

The number of knitted mitten is 20

Step-by-step explanation:

Given as :

The cost of each knitted scarves = $50

The cost of pairs of mittens = $25

Total number of scarves and mitten bought = 30

The total money invested to pay for items = $1000

Let The number of knitted scarves = k

Let The number of mitten = m

<u>Now, According to question</u>

The total money invested to pay for items = cost of each knitted scarves × number of knitted scarves + cost of pairs of mittens × number of mitten

i.e $1000 = $50 × k + $25 × m

Or, 40 = 2 k + m

i.e 2 k + m = 40           ........A

And

Total number of scarves and mitten bought =  number of knitted scarves +  number of mitten

i.e k + m = 30            ...........B

Now, solving eq A and eq B

So, (2 k + m ) - ( k + m ) = 40 - 30

Or, (2 k - k) + ( m - m) = 10

Or, k + 0 = 10

∴  k = 10

So,  The number of knitted scarves = k = 10

Put the value of k into eq B

∵ k + m = 30

So, m = 30 - k

or, m = 30 - 10

∴  m = 20

The number of knitted mitten = m = 20

Hence,  The number of knitted scarves is 10 and The number of knitted mitten is 20  . Answer

7 0
3 years ago
The function f(t) = t2 + 4t − 14 represents a parabola. Part A: Rewrite the function in vertex form by completing the square. Sh
Cloud [144]

Answer:

A)  The vertex ( h , k) = ( -2 , -18)

B) The minimum value of the given function = - 18

C) The Axis of the symmetry for f(t) is y -axis

Step-by-step explanation:

A)

Given a parabola   f(t) = t² + 4 t − 14

                               f(t) =  t² + 2(2) t + (2)²-4− 14

                           f(t) = (t +2)² - 18

Let comparing  y = (x +2)² -18

                   (x +2)² = y + 18

                   (x-h))² = 4 a ( y - k))²

<em>The vertex ( h , k) = ( -2 , -18)</em>

B)

  Given a parabola   f(t) = t² + 4 t − 14

  Differentiating with respective to 't'

                                 f¹(t) = 2 t + 4

                                  f¹(t) = 2 t + 4 = 0

now                      t = \frac{-4}{2} = -2

Again Differentiating with respective to 't'

                    f^{ll} (t) = 2 (1) >0

f(x) has a minimum value at t = -2

Given f(t) = t² + 4 t − 14

         f( -2) = 4 + 4(-2) -14 = 4 -8 -14 = -18

The minimum value of the given function = - 18

C)

f(t) = (t +2)² - 18

Let comparing  y = (x +2)² -18

                   (x +2)² = y + 18

                   (x-h))² = 4 a ( y - k))²

The vertex ( h , k) = ( -2 , -18)

The Axis of the symmetry for f(t) is y -axis

8 0
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