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Musya8 [376]
3 years ago
13

How many subsets are there of set A

Mathematics
1 answer:
nignag [31]3 years ago
5 0
You didn’t add a picture, so it’s impossible to answer
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If X= 4 solve this equation: <br><br><br> 2x + 3=
nlexa [21]

Answer:

11

Step-by-step explanation:

2x + 3

2(4) + 3 .......................replace x with 4

8 + 3

11

4 0
3 years ago
Read 2 more answers
A garden is rectangular with an area of 6/7 square miles. If the length of the garden is 3/5 miles, what is its width?
Dafna11 [192]

Answer:

Step-by-step explanation:

Area= length x width

area=6/7, length=3/5, width=?

6/7=3/5 x width

6/7 divided by 3/5= 6/7 x 5/3 (you have to multiply by the recipricol, or flip the fraction.)

6/7 x 5/3=30/21= 1 3/7=width

7 0
3 years ago
Translate the sentence into an inequality.
blagie [28]

Let the no be x

Inequality given by

\\ \sf\longmapsto 2(x-4)\leqslant -18

Let's solve

\\ \sf\longmapsto x-4\leqslant -9

\\ \sf\longmapsto x\leqslant -5

3 0
2 years ago
Read 2 more answers
Chan deposited money into his retirement account that is compounded annually at an interest rate of 7%. Chan thought the equival
dedylja [7]

Answer:

No, equivalent quarterly rate will be approx 1.75%

Step-by-step explanation:

Given that Chan deposited money into his retirement account that is compounded annually at an interest rate of 7%.

We know that there are 4 quarters in 1 year.

So to find that equivalent quarterly we will divide given yearly rate by number of quarters.

That means divide 7% by 4.

which gives 1.75%.

But that is different than Chan's though of 2% quarterly interest.

Hence Chan is wrong.

4 0
3 years ago
A farmer wants to fence a rectangular area of 72 square feet next to a river. Find the length and width of the rectangle which u
Arlecino [84]

Answer:

  • 12 ft parallel to the river
  • 6 ft perpendicular to the river

Step-by-step explanation:

The least fence is used when half the total fence is parallel to the river. That is, the shape of the rectangle is twice as long as it is wide.

72 = W(2W)

36 = W²

6 = W . . . . . . the width perpendicular to the river

12 = 2W . . . .  the length parallel to the river

_____

<em>Development of this relation</em>

Let T represent the total length of the fence for some area A. Then if x is the length along the river, the width is y=(T-x)/2, and the area is ...

  A = xy = x(T -x)/2

Note that the equation for area is that of a parabola with zeros at x=0 and at x=T. That is, for some fence length T, the area will be a maximum at the vertex of this parabola. That vertex is located halfway between the zeros, at ...

 x = (0 +T)/2 = T/2

The corresponding area width (y) is ...

  y = (T -T/2)/2 = T/4

Equivalently, the fence length T will be a minimum for some area A when x=T/2 and y=T/4. This is the result we used above.

8 0
3 years ago
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