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mr_godi [17]
3 years ago
13

Point R(4,-5) is reflected across the y-axis to point S. Point S is reflected across the x-axis to point T. What are the coordin

ates of point T. What are the coordinates of point T? Use words and numbers to explain your answer.
Mathematics
1 answer:
Naddika [18.5K]3 years ago
3 0
You need a graft so that you can do that
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A vector is in standard position, with its terminal point in the second quadrant and an x-coordinate of –5. The vector has a mag
joja [24]

a.

The y-coordinate of the vector with its terminal point in the second quadrant is 6.

The magnitude of the vector, r = √(x² + y²) where x = x-coorcinate of vector = -5 and y = y-coordinate of vector.

Since r = √61 and r = √(x² + y²)

Making y subject of the formula, we have

y = √(r² - x²)  

Substituting the values of the variables into the equation, we have

y = √((√61)² - (-5)²)  

y = √(61 - 25)  

y = ±√36

y = ±6

Since r is in the second quadrant, its y-coordinate is positive.

So, y = 6

So, the y-coordinate of the vector with its terminal point in the second quadrant is 6.

b.

The direction angle of the vector with its terminal point in the second quadrant is 130°

The direction angle of the vector is gotten from tanФ = y/x

Subsstituting x and y into the equation, we have

tanФ = y/x

tanФ = 6/-5

tanФ = -1.2

tan(180° - Ф) = 1.2

Taking inverse tan of both sides, we have

180° - Ф = tan⁻¹(1.2)

180° - Ф = 50.2°

Ф = 180° - 50.2°

Ф = 129.8°

Ф ≅ 130° to the neares whole number

The direction angle of the vector with its terminal point in the second quadrant is 130°.

Learn more about vectors here:

brainly.com/question/18478651

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I have two congruent sides. I also have two congruent angles that measure 45 degree each. I am a
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