<h3>The number of pears Amy has is 16.</h3>
Step-by-step explanation:
Let J represent the number of pears Josh has.
Let L represent the number of pears Leya has.
Let A represent the number of pears Amy has.
From the question given above,
Josh (J) = 4 × Leya (L)
J = 4L ....... (1)
Leya (L) = ½ × Amy (A)
L = ½A ........ (2)
Next, we shall determine the number of pears Leya has. This can be obtained as follow:
From equation 1
J = 4L
But
Josh (J) = 32 pears
Thus,
32 = 4L
Divide both side by 4
L = 32 / 4
<h3>Leya (L) = 8 pears </h3>
Finally, we shall determine the number pears Amy has. This can be obtained as follow:
From equation 2
L = ½A
But
Leya (L) = 8 pears
Thus,
8 = ½A
Cross multiply
A = 8 × 2
<h3>Amy (A) = 16 pears </h3>
Therefore, Amy has 16 pears.
Learn more: brainly.com/question/20971657
Answer:
y=1/2×2-1
Step-by-step explanation:
x2 – y = 0 yields a parabola.
y = x is straight but has a slope to make it increase/decrease.
2y = x2 yields a parabola.
x2 = 0 yields a parabola.
Answer:
The correct option is (b).
Step-by-step explanation:
If X
N (µ, σ²), then
, is a standard normal variate with mean, E (Z) = 0 and Var (Z) = 1. That is, Z
N (0, 1).
The distribution of these z-variate is known as the standard normal distribution.
The mean and standard deviation of the active minutes of students is:
<em>μ</em> = 60 minutes
<em>σ </em> = 12 minutes
Compute the <em>z</em>-score for the student being active 48 minutes as follows:

Thus, the <em>z</em>-score for the student being active 48 minutes is -1.0.
The correct option is (b).
Central angle is 130
Semi circle is BED and BCD
Major arc is CEB
Measure BAC is 130
BEC is 230