H2O
This equation is a double displacement reaction, and it forms H2CO3, which is very unstable and separates into H2O and CO2.
Phosphoric acid has 3 pKa values (pKa1=2.1, pKa2=6.9, pKa3= 12.4) and after 3 ionization it gives 3 types of ions at different pKa values:
H₃PO₄(aq) + H₂O(l) ⇌ H₃O⁺(aq) + H₂PO₄⁻ (aq) pKₐ₁
<span>
</span>H₂PO₄⁻(aq) + H₂O(l) ⇌ H₃O⁺(aq) + HPO₄²⁻ (aq) pKₐ₂
HPO₄²⁻(aq) + H₂O(l) ⇌ H₃O⁺(aq) + PO₄³⁻ (aq) pKₐ₃
The last equilibrium is associated with the highest pKa value (12.4) of phosphoric acid. There the last OH group will lose its hydrogen and hydrogen phosphate ion (HPO₄²⁻) turns into phosphate ion (PO₄³⁻).
Answer:
u = 0.176 m/x
Explanation:
∴ n O2 = 1 mol
∴ mass O2 = 1 mol * 32 g/mol = 32 g
∴ T = 60°C = 333 K
∴ P = 5 bar
⇒ V = RTn/P = (83.14 bar.cm³/mol.K)*(333 K)*(1 mol))/(5 bar)
⇒ V = 5537.124 cm³
∴ d = 20cm
⇒ A = (1/4π)*d² = 314.16 cm²
velocity of the gas (m/x):
- u = m / ρ*A
- let time (t) = x sec
∴ ρ = 32 g / 5537.124 cm³ = 5.78 E-3 g/cm³
∴ mass flow rate (m) = 32g / x
⇒ u = (32 g/x) / (( 5.78 E-3 g/cm³)*(314.16cm²))
⇒ u = 17.625 cm/x * ( m/100cm) = 0.176 m/x
