Answer: ![A=15000(1.30)^t](https://tex.z-dn.net/?f=A%3D15000%281.30%29%5Et)
Step-by-step explanation:
Formula to find the price of an item after t years after withe a depreciation rate of r% is
, where P = Initial value of item.
Given: P = $15,000, r= 30%
Then, the value of car after t years will be :
![A= 15000(1+\dfrac{30}{100})^t\\\\\Rightarrow\ A=15000(1+0.30)^t\\\\\Rightarrow\ A=15000(1.30)^t](https://tex.z-dn.net/?f=A%3D%2015000%281%2B%5Cdfrac%7B30%7D%7B100%7D%29%5Et%5C%5C%5C%5C%5CRightarrow%5C%20A%3D15000%281%2B0.30%29%5Et%5C%5C%5C%5C%5CRightarrow%5C%20A%3D15000%281.30%29%5Et)
The required general formula for the value of the car t years after its purchase:
![A=15000(1.30)^t](https://tex.z-dn.net/?f=A%3D15000%281.30%29%5Et)
(0,4) (0,-2) (-2,0)
for the reflection over the x-axis, all the y values go to their opposite (0,-4) (0,2) (2,0)
then at the rotation it goes (-x,-y) and becomes (0,4) (0,-2) (-2,0)
Hopefully this helps: 16(x^2 + 6x + y^2) = 5(8y + 63)
I'm not sure where to take it from there, but hopefully someone can build off of that. :)
Answer:
61
Step-by-step explanation:
3 x 4 x 5 = 60
30 + 1 = 61
Answer:
ma'am that screen is black ⚫