Question

Can I please get help on these questions?

Answer 1

Well, let's see that we can find the midpoint with this formula:

$(\frac{x_1+x_2}{2},\frac{y_1+y_2}{2})$

We have the midpoint and one of the endpoints so:

$(\frac{x_1+(-2)}{2},\frac{y_1+(-19)}{2})=(-1,-28)$

$(\frac{x_1-2}{2},\frac{y_1-19}{2})=(-1, -28)$

We have this now:

$\frac{x_1-2}{2}=-1$

$x_1-2= -1.2$

$x_1-2=-2$

$x_1=-2+2$

$x_1=0$

$\frac{y_1-19}{2}=-28$

$y_1-19=-28.2$

$y_1-19=-56$

$y_1=-56+19$

$y_1=-37$

So the pair is (0, -37)

Answer 2

Answer:

The answer to your question is: midpoint (0, -37)

Step-by-step explanation:

Data

midpoint = (-1, -28)

endpoint = (-2,-19)

Formula

mp = (ip +ep)/2

clear ip

ip = 2mp -ep

Calcule x

Xip = 2 (-1) - 2  = -2 -2 = -0

Yip = 2(-28) - -19 = -56 + 19 = -37