Question

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Answer 1

Answer:

The value of given function

A)  f(0) = 0

B)  f(18) = 9

C) f( - 18) = - 9

Step-by-step explanation:

Given as :

The function of x is given as

f(x) = $\dfrac{x}{2}$

So, for every value of x , the value of function of x changes

A) for x = 0

f(0) = $\dfrac{0}{2}$

i.e f(0) = 0

B) for x = 18

f(18) = $\dfrac{18}{2}$

i.e f(18) = 9

C) for x = - 18

f( -18) = $\dfrac{ -18}{2}$

i.e f(-18) = - 9

So, The value of f(0) = 0  , f(18) = 9  , f( - 18) = - 9

Hence, The value of given function

A)  f(0) = 0

B)  f(18) = 9

C) f( - 18) = - 9  Answer

Answer 2

Answer:

The values for the given function f is defined by $f(x)=\frac{1}{2}x$ is

a) $f(0)=0$ ,

b) $f(18)=9$ and

c) $f(-18)=-9$

Step-by-step explanation:

Given that the function f is defined by $f(x)=\frac{1}{2}x$

Now to find the value of f(0), f(18) and f(-18)

Now take f(0)

Put x=0 in the given function $f(x)=\frac{1}{2}x$ we get

$f(0)=\frac{1}{2}(0)$

$=0$

Therefore $f(0)=0$

Put x=18 in the given function $f(x)=\frac{1}{2}x$ we get

$f(18)=\frac{1}{2}(18)$

$=9$

Therefore $f(18)=9$

Put x=-18 in the given function $f(x)=\frac{1}{2}x$ we get

$f(-18)=\frac{1}{2}(-18)$

$=-9$

Therefore $f(-18)=-9$

The values for the given function f is

a) $f(0)=0$ ,

b) $f(18)=9$ and

c) $f(-18)=-9$